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Kamila [148]
4 years ago
12

Which changes to observed time and length occur when objects approach the speed of light?

Physics
1 answer:
mixas84 [53]4 years ago
3 0

Answer:

Time moves slower and length decreases.

Explanation:

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What did Thomson contribute to the model of atom
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<h3><u>Answer;</u></h3>

<em>Electrons </em>

<h3><u>Explanation;</u></h3>
  • <em><u>Thomson contributed to the model of an atom by discovery of </u></em><em><u>electrons </u></em><em><u>and thus proving the existence of sub-atomic particles in an atom. </u></em>
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light inside the thin glass tube of a laparoscopic surgical device strikes the edge of the glass tube and is entirely reflected
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Light striking the walls of the glass cylinder and reflecting in inside tube itself is a phenomenon known as total internal reflection.

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Reflection is often synonymous with the verbs cogitate, contemplate, reason, hypothesize, and think. All of these expressions mean "using one's intellect, judgment, or inference faculties," but the word "reflect" means carefully considering a recollection.

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constant verb When you ruminate, you seriously consider something. Alternatives include thinking, analyzing, planning, and thinking. More phrases containing "reflect" Reflecting feelings is the act of observing a person's verbal and nonverbal signs for their emotions and feelings, then immediately communicating (or reflecting) those attitudes to the user or customer.

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6th grade science !!!!!!!!!!!!!!!​
posledela

Answer:

71

Explanation:

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3 years ago
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Answer:

So what's the answer???

Explanation:

8 0
3 years ago
A 1090 kg car has four 12.7 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to ro
max2010maxim [7]

Answer:

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

Explanation:

To develop this exercise we proceed to use the kinetic energy equations,

In the end we replace

KE_{Total}=KE_{Translational}+KE_{Rotational}

KE_{Total}=\frac{1}{2}m_{car}+4*\frac{1}{2}*I*(\frac{v}{r})^2

Here

I=\frac{1}{2}m_{wheels}*r^2 meaning the 4 wheels,

So replacing

KE_{Rotational}=4\frac{1}{2}*(\frac{1}{2}m_{wheels}*r^2)*(\frac{v}{r})^2=m*v^2

So,

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}*v^2}{\frac{1}{2}m_{car}*v^2+m_{wheels}*v^2}

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}}{\frac{1}{2}m_{car}+m_{wheels}}

\frac{KE_{Rotational}}{KE_{Total}} =  \frac{10}{545+10}

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

3 0
3 years ago
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