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UNO [17]
3 years ago
9

Jet fighter planes are launched from aircraft carriers with the aid of their own engines and a catapult. If in the process of be

ing launched from rest, the thrust of a jet's engines is 2.50 x 10^5 N and after moving through a distance of 90 m the plane lifts off with a kinetic energy of 5.40 x 10^7 J, what is the work done on the jet by the catapult?
Physics
1 answer:
ANTONII [103]3 years ago
5 0

Answer:

W=315 x 10⁵ J

Explanation:

Given that

F= 2.5 x 10⁵ N

d= 90 m

K.E.=5.4 x 10⁷ J

We know that work done by all force is equal to the change in kinetic energy

Lets take work done by catapult is W

W + F.d= K.E.

W= 5.4 x 10⁷ -  2.5 x 10⁵  x 90 J

W= (540 - 25 x 9) 10⁵ J

W=315 x 10⁵ J

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alexdok [17]

The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

<h3>What is the angular velocity of the propeller?</h3>

The angular velocity of the propeller in rad/s is given as follows:

  • 1 rev/m = 2π/60 rad/s.

1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.

b. The linear velocity, v = radius * angular velocity

Linear velocity, v = 2.25/2 * 136.1

v = 153.1 m/s

c. Centripetal acceleration, a = \frac{v^{2}}{r}

a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}

Centripetal acceleration in terms of g; g = \frac{20835.2}{9.81} = 2123.8 g

Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948

#SPJ1

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