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3 years ago

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The velocity-time and acceleration-time graphs of a particle are given here. Its position-time graph may be given as: PLZ answer

fast!!!!! I will mark best as BRAINLEST!!!!!!! PLZ!!! TEST IN 2O MINS

1 answer:

artcher [175]3 years ago

8 0

Answer:

I would say the answer is B

Explanation:

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Protons and neutrons are located in the nucleus of the atom.

Shtirlitz [24]

Answer:

True

Explanation:

The nucleus contains all of the mass of the atom. Almost all of the mass of the atoms is made up of protons and neutrons.

3 0

3 years ago

Read 2 more answers

A series circuit has a capacitor of 0.25 × 10⁻⁶ F, a resistor of 5 × 10³ Ω, and an inductor of 1H. The initial charge on the cap

viktelen [127]

Answer:

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

Explanation:

As we know that they are in series so the voltage across all three will be sum of all individual voltages

so it is given as

$V_r + V_L + V_c = V_{net}$

now we will have

$iR + L\frac{di}{dt} + \frac{q}{C} = 12 V$

now we have

$1\frac{d^2q}{dt^2} + (5 \times 10^3) \frac{dq}{dt} + \frac{q}{0.25 \times 10^{-6}} = 12$

So we will have

$q = 3\times 10^{-6} + c_1 e^{-4000 t} + c_2 e^{-1000 t}$

at t = 0 we have

q = 0

$0 = 3\times 10^{-6} + c_1 + c_2$

also we know that

at t = 0 i = 0

$0 = -4000 c_1 - 1000c_2$

$c_2 = -4c_1$

$c_1 = 1 \times 10^{-6}$

$c_2 = -4 \times 10^{-6}$

so we have

$q = (3 + e^{-4000 t} - 4 e^{-1000 t})\times 10^{-6}$

at t = 0.001 we have

$q = 1.55 \times 10^{-6} C$

at t = 0.01

$q = 2.99 \times 10^{-6} C$

at t = infinity

$q = 3 \times 10^{-6} C$

5 0

3 years ago

Un avión vuela a 10000m de altura y otro a 33300 pies, si un pie equivale a 30.48cm ¿Cuál vuela a mayor altura?

user100 [1]

Answer:

Avion A (10000 meters).

Explanation:

Deje que la altura de los aviones sea A y B respectivamente.

Dados los siguientes datos;

Altura A = 10000 metros

Altura B = 33300 pies

Para encontrar el avión que voló más alto, tendríamos que hacer alguna conversión de unidades.

Conversión:

Metros a centímetros;

1 metro = 100 cm

10000 metros = 100 * 10000 = 1.000.000 centímetros.

Por lo tanto, la altura A en cm = 1,000,000 centímetros

Pies a centímetros;

1 pie = 30,48 centímetros

33300 pies = 33300 * 30,48 = 1014984 centímetros.

Por lo tanto, la altura B en cm = 1014984 centímetros.

De los cálculos anteriores, podemos deducir que el avión A voló más alto.

6 0

3 years ago

2. Elements in the same group have similar properties because they have O the same number of protons O the same number of valenc

NARA [144]

The same number of valence electrons

3 0

3 years ago

I need some help w/ this:

pochemuha

Answer:

The velocity of the police car is, v = 17.798 m/s

Explanation:

Given data,

The actual frequency of the siren, f = 2010 Hz

The observed frequency of siren is, f' = 2120 Hz

The velocity of the observer, v' = 0 m/s

The velocity of the source, v = ?

The formula for Doppler effect,

$f'=\frac{(V+v')}{(V-v)}f$

Where,

V - velocity of sound waves in air.

$v=V-(V+v')\frac{f}{f'}$

Substituting the given values,

$v=343-(343+0)\frac{2010}{2120}$

v = 17.798 m/s

Hence, the velocity of the police car is, v = 17.798 m/s

5 0

2 years ago