Question

In a drill during basketball practice, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds. The magnitude of the player's average velocity during the drill is...
1. 0 m/s
2. 0.5 m/s
3. 1 m/s
4. 1.5 m/s
5. 3 m/s
6. 30 m/s

Answer 1

Answer:

0 m/s

Explanation:

Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.

In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.

As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.

Average velocity = displacement/time

v=0/30

v = 0 m/s

Hence, the correct option is (1).