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3 years ago

What factors cause a rock to become metamorphic

Physics

2 answers:

kipiarov [429]3 years ago

5 0

Pressure and heat causes a rock to become metamorphic

Lynna [10]3 years ago

3 0

Pressure and heat. I hope this helps

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Cold syrup flows sluggishly because of??

Eva8 [605]

Answer:

Water is very different from honey, syrup, glycerine, or oil. It pours easily and is not thick and sticky like the others. The property that determines how easily a liquid pours is called VISCOSITY. Water has a low viscosity; syrup has a high viscosity. Liquids with a high viscosity are said to be viscous.

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3 years ago

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LIst properties common to many organic compounds

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Some properties I know are melting point, boiling point, and index of refraction.

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3 years ago

A 1.0 kg block is attached to an unstretched

KonstantinChe [14]

Answer:

Change in potential energy of the block-spring-Earth

system between Figure 1 and Figure 2 = 1 Nm.

Explanation:

Here, spring constant, k = 50 N/m.

given block comes down eventually 0.2 m below.

here, g = 10 m/s.

let block be at a height h above the ground in figure 1.

⇒In figure 2, potential energy of the block-spring-Earth

system = m×g×(h - 0.2) + 1/2× k × x². where, x = change in spring length.

⇒ Change in potential energy of the block-spring-Earth

system between Figure 1 and Figure 2 = (m×g×(h - 0.2)) - (1/2× k × x²)

= (1×10×0.2) - (1/2×50×0.2×0.2) = 1 Nm.

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3 years ago

1 Apply Look around you to an object in motion. Describe the motion by discussing its position and direction of motion in relati

luda_lava [24]

Most of the problem depends on which object you observe. For the speed, take the absolute value of the derivative of the polynomial interpolation of position verses time.

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3 years ago

A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static fr

PSYCHO15rus [73]

Answer:

ω = 2.1 rad/sec

Explanation:

As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.
This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.
Now, we need to ask ourselves: what supplies this force?
In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.
We know that this force can be expressed as follows:

$f_{frs} = \mu_{s} * F_{n} (1)$

where μs = coefficient of static friction between the rock and the merry-

go-round surface = 0.7, and Fn = normal force.

In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:
Fn = m*g (2)
This static friction force is just the same as the centripetal force.
The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:

$F_{c} = m* \omega^{2}*r (3)$

Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:

$\omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec$

This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.

4 0

3 years ago