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Romashka [77]
3 years ago
15

A biker pedals hard to ride his bike to the top of a 44 m hill. He decides to let his bike coast down the hill, and is having so

much fun coasting that he decided not to pedal even climbing the next hill. If that hill is 10 m high, what will the biker s speed be at the top of that hill?
Physics
1 answer:
Vanyuwa [196]3 years ago
7 0

The biker's speed at the top of the second hill is 25.8 m/s

Explanation:

The problem can be solve by applying the law of conservation of energy. In absence of frictional forces, the total mechanical energy of the bike (the sum of potential energy + kinetic energy) must be conserved. So we can write:

U_i +K_i = U_f + K_f

where

U_i is the initial potential energy at the top of the first hill

K_i is the initial kinetic energy at the top of the first hill

U_f is the final potential energy at the top of the second hill

K_f is the final kinetic energy at the top of the second hill

We can rewrite the equation as:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m is the mass of the bike

g=9.8 m/s^2 is the acceleration of gravity

h_i = 44 m is the height of the first hill

u = 0 m/s is the speed at the top of the first hill

h_f = 10 m is the height of the second hill

v is the speed at the top of the second hill

And solving for v, we find:

mgh_i = mgh_f + \frac{1}{2}mv^2\\v^2=\sqrt{2g(h_i-h_f)}=\sqrt{2(9.8)(44-10)}=25.8 m/s

Learn more about kinetic energy and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647  

brainly.com/question/10770261  

#LearnwithBrainly

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A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car
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Answer:

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Explanation:

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d = vt + \frac{1}{2}at²

523 = (0)t + (\frac{1}{2})(5.5)t²

523 = 2.8t²

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