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zimovet [89]
2 years ago
11

Describe the general relationship between the weight of adult men and the average number of Calories needed daily to maintain a

steady weight.
Physics
1 answer:
Alexeev081 [22]2 years ago
3 0

Answer:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking.

The amount of calories contained in the food we eat every day must represent the amount of calories eliminated by the body in that time to have a steady weight.

Explanation:

The average number of calories needed daily represents the average quantity of calories eliminated by human body due to metabolism and must be compensated by eating and drinking. If total quantity of calories in the food we consume every day is higher that the average number of calories needed daily, then weight increases by fat accumulation.

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At one particular moment, a 19.0 kg toboggan is moving over a horizontal surface of snow at 4.00 m/s. After 7.00 s have elapsed,
Lina20 [59]

Answer:

10.86 N

Explanation:

Let the average frictional force acting on the toboggan be 'f' N.

Given:

Mass of toboggan (m) = 19.0 kg

Initial velocity (u) = 4.00 m/s

Final velocity (v) = 0 m/s

Time for which friction acts (Δt) = 7.00 s

Now, change in momentum is given as:

\Delta p =Final\ momentum-Initial\ momentum\\\\\Delta p=mv-mu\\\\\Delta p=19.0\ kg(0-4.00)\ m/s\\\\\Delta p=-76.00\ Ns

Now, we know that, change in momentum is equal to the impulse acting on the body. So,

Impulse is, J=\Delta p=-76.00\ Ns

Now, we know that, impulse is also given as the product of average force and the time interval for which it acts. So,

J=f\times \Delta t

Rewriting the above equation in terms of 'f', we get:

f=\dfrac{J}{\Delta t}

Plug in the given values and solve for 'f'. This gives,

f=\frac{-76.00\ Ns}{7.00\ s}\\\\f=-10.86\ N

Therefore, the magnitude of frictional force is |f|=|-10.86\ N|=10.86\ N

3 0
3 years ago
A student is measuring the circumferences of pine trees for an experiment.
Artemon [7]

Answer:

Her measurements will be more accurate if she uses a cloth tape

measure instead of a ruler.

Explanation: (apex)

7 0
3 years ago
A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
Nataly_w [17]

Answer:

0.092 m

Explanation:

A charged moving particle immersed in a region with magnetic field follows a circular trajectory at constant speed (uniform circular motion), since the magnetic forces acts perpendicular to the direction of motion of the particle.

Since the magnetic force acts as centripetal force, we can write:

qvB=m\frac{v^2}{r}

where

q is the charge of the particle

v is its velocity

B is the strength of the magnetic field

m is the mass of the particle

r is the radius of the orbit

Solving the equation for r,

r=\frac{mv}{qB}

For the ion of oxygen-16, we have:

m_A=2.66\cdot 10^{-26}kg

q_A = 1.6\cdot 10^{-19}C (it is singly charged)

v_A=2.90\cdot 10^6 m/s

B_A=1.30 T

So the radius of its orbit is

r_A=\frac{m_A v_A}{q_A B_A}=\frac{(2.66\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.371 m

For the ion of oxygen-18, we have:

m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg

q_B = 1.6\cdot 10^{-19}C (it is singly charged)

v_B=2.90\cdot 10^6 m/s

B_B=1.30 T

So the radius of its orbit is

r_B=\frac{m_B v_B}{q_B B_B}=\frac{(2.99\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.417 m

After each ion has travelled a semicircle, the separation between the two ions will be twice the difference in their radius, so:

d=2(r_B-r_A)=2(0.417-0.371)=0.092 m

3 0
3 years ago
Science help please!
OLga [1]

Answer:

104 N

Explanation:

m = 1300 kg

a = 0.08m/s^2

F = 1300*0.08

F = 104 N

Newtons is the unit of force.

3 0
3 years ago
The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
Alexeev081 [22]

Answer: a=-2.4525 m/s^2

d=s=190.3 m

Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr

Fr = 25% of weight

W=mg

W=1750*9.81

W=17167.5

Hence

Fr=\frac{25}{100} * -17167.5\\\\Fr=-4291.875 N

Frictional force is negative as it acts in opposite direction

According to newton second law of motion

F=ma

hence

a=Fr/m

a=-4291.875/1750\\a=-2.4525

given

u= 110 km/h

u=110*1000/3600

u=30.55 m/s

to get t we know that final velocity v=0

v^2=u^2+2as\\0=30.55^2-2*2.4525*s\\s=190.34m

3 0
2 years ago
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