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3 years ago

If you somehow added a proton to a calcium atom, it would be

1 answer:

5 0

Adding a proton to a calcium atom would change its identity, it would no longer be a Calcium atom. It would be a Scandium (Sc) atom.

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Consider the following unbalanced redox reactions. In each case, separate the whole reactions into half-reactions, balance the h

Marina86 [1]

Answer & Explanation:

(a)

$Fe^{2+} +NO_{3}^{-} => Fe{(OH)}_3 + N_2$

reducing agent = Fe²⁺

Oxidizing agent = NO₃⁻

oxidation

Fe²⁺ ⇒ Fe(OH)₃

reduction

NO₃⁻ ⇒ N₂

Oxidation Half Reaction

(redox reactions are balanced by adding appropriate H⁺ and H₂O atoms)

Fe²⁺ ⇒ Fe(OH)₃

Balance O atoms

Fe²⁺ + 3H₂O ⇒ Fe(OH)₃

Balance H atoms

Fe² + 3H₂0 ⇒ Fe(OH)₃ + 3H⁺

balance Charge

Fe² + 3H₂0 ⇒ Fe(OH)₃ + 3H⁺ + e⁻..............(1)

reduction Half Reaction

NO₃⁻ ⇒ N₂

Balance N atoms

2NO₃⁻ ⇒N₂

Balance O atoms by adding appropriate H₂O

2NO₃⁻ ⇒ N₂ + 6H₂O

Balance H atoms

2NO₃⁻ + 12H⁺ ⇒ N₂ + 6H₂O

Balance Charge

2NO₃⁻ + 12H⁺ + 10e⁻⇒ N₂ + 6H₂O.................(2)

Combine Equation (1) and (2)

(1) × 10: 10Fe² + 30H₂0 ⇒ 10Fe(OH)₃ + 30H⁺ + 10e⁻

(2) × 1: 2NO₃⁻ + 12H⁺ + 10e⁻⇒ N₂ + 6H₂O

(1) + (2): 10Fe² + 30H₂0 + 2NO₃⁻ + 12H⁺ + 10e⁻ ⇒10Fe(OH)₃ + 30H⁺ + 10e⁻ +

N₂ + 6H₂O

10Fe² + 24H₂0 + 2NO₃⁻ ⇒ 10Fe(OH)₃ + 18H⁺ + N₂

this is the balanced reaction

REDUCTION POTENTIAL

10Fe²⁺(aq) + 10e⁻ ⇒ 10Fe(OH)₃(aq) E°ox = 10(-0.44) = -4.4V

2NO₃⁻(aq) - 2e⁻ ⇌ N₂(g) + 18H⁺ E°red = 2(+0.80) = +1.6

10Fe² + 24H₂0 + 2NO₃⁻ ⇒ 10Fe(OH)₃ + 18H⁺ + N₂ E°cell = -2.8V

E°cell = E°red + E°ox

4 0

4 years ago

N2(g) + 3H2(g) →2NH3(g)

monitta

Answer:

2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction

Explanation:

In reaction:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

You can see that the stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) requires the following amounts of reagents and are produced:

N₂: 1 mole
H₂: 3 moles
NH₃: 2 moles

The following three rules can apply:

If 2 moles of NH₃ are produced from 1 mole of N₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of N₂ are produced?

$moles of N_{2} =\frac{5 moles of NH_{3} *1 mole of N_{2} }{2 moles of NH_{3}}$

moles of N₂= 2.5

If 2 moles of NH₃ are produced from 3 moles of H₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of H₂ are produced?

$moles of H_{2} =\frac{5 moles of NH_{3} *3 mole of H_{2} }{2 moles of NH_{3}}$

moles of H₂= 7.5

2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction

6 0

3 years ago

Which two factors are used to calculate the kinetic energy of an object?

muminat

Answer:

Mass and Velocity

Explanation:

hope this is the right answer might wrong tho

3 0

3 years ago

Read 2 more answers

What is light energy

wlad13 [49]

Answer:

Light energy is a form of electromagnetic radiation. Light consists of photons, which are produced when an object's atoms heat up. Light travels in waves and is the only form of energy visible to the human eye.

Explanation:

8 0

4 years ago

Read 2 more answers

What is the systematic or IUPAC name for SO2

Zinaida [17]

Answer:

Sulfur trioxide

Sulfur trioxide | SO3 - PubChem.

Explanation:

3 0

3 years ago