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irinina [24]
3 years ago
12

If you somehow added a proton to a calcium atom, it would be

Chemistry
1 answer:
ahrayia [7]3 years ago
5 0
Adding a proton to a calcium atom would change its identity, it would no longer be a Calcium atom. It would be a Scandium (Sc) atom.
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A chemist must dilute 34.3mL of 1.72mM aqueous calcium sulfate solution until the concentration falls to 1.00mM. He'll do this b
EastWind [94]

Answer:

58.9mL

Explanation:

Given parameters:

Initial volume  = 34.3mL    = 0.0343dm³

Initial concentration  = 1.72mM   = 1.72 x 10⁻³moldm⁻³

Final concentration  = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume  =?

Solution:

Often times, the concentration of a standard solution may have to be diluted to a lower one by adding distilled water. To find the find the final volume, we must recognize that the number of moles of the substance in initial and final solutions are the same.

   Therefore;

              C₁V₁  =  C₂V₂

where C and V are concentration and 1 and 2 are initial and final states.

        now input the variables;

                      1.72 x 10⁻³ x  0.0343 = 1 x 10⁻³  x V₂

                        V₂ = 0.0589dm³ = 58.9mL

         

4 0
3 years ago
Chemicals that are able to slow or stop the reaction rate are inhibitors. reactants. products. catalysts.
erma4kov [3.2K]

Answer:inhibitors

Explanation:

I just took the quiz .

7 0
3 years ago
Read 2 more answers
What are two ways in which white blood cells fight pathgons that have entered the body​
crimeas [40]

Answer:

Answer c i believe

Explanation:

3 0
3 years ago
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem
Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

R=0.08205L.atm/mol.K

R=8.3145L.kPa/mol.K

R=8.3145J/mol.K 

R=1.987cal/mol.K

R=0.08314L.bar/mol.K

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

3 0
3 years ago
Can someone help me with this molar mass problem?[It’s the last one]
quester [9]

Answer:

54.18 \times 10^{23} \ moles in 3 mole of  Al_2(SO_4)_3

Explanation:

It is clear that in the given 1\ mole of Al_2(SO_4)_3 have 3\ ions of SO_4^2^-

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Since 1 ion of anything is equivalent to 6.02\times10^{23} \ moles

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Which is equivalent to 9 \times6.02\times10^{23}=54.18\times10^{23} \ moles

Thus 3 moles of  Al_2(SO_4)_3 gives 54.18\times10^{23} \ moles of  SO_4^2^-.

5 0
4 years ago
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