Answer:
v = 4374 Km/h
Explanation:
Given that,
Mass of the smaller object, m = 2 Kg
Mass of the bigger object, M = 1500 Kg
Velocity of the bigger object, V = 1.62 m/s
Velocity of the smaller object, v = ?
The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula
p = mv Kg m/s
To find the momentum of the bigger object, substitute M and V in the above equation
p = 1500 Kg x 1.62 m/s
= 2430 Kg m/s
The velocity imparted to the small body to attain this momentum is given by the relation
v = p/m m/s
= 2430 Kg m/s / 2 Kg
= 1215 m/s
By converting the velocity to Km/h
v = 4374 km/h
Hence, the velocity of the 2 Kg object is v = 4374 km/h
Answer:
Explanation:
Given that,
Orbital period, T = 42.5 hours = 153000 seconds
The average distance of Jupiter's mass, r = 422,000 km
We need to find Jupiter's mass. The formula for the orbital period is given by :
So, the mass of Jupiter is 
.
There are 60 minutes in an hour. Whatever distance a person crosses in 5 mins, he/she can cross 12 times that distance in 1 hour. So, in one hour the person could have crossed 12 X 600 = 7200 meters.
But, 1000 meters equal one kilometer. So, 7200m = 7.2 km. Thus, this person travels 7.2 km in one hour, and hence has a speed of 7.2 km/hr
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by
<span>C = 2L = 2*pi*R ---> R = L/pi </span>
<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>
<span>we can define a small charge dq as </span>
<span>dq = l*ds = l*R*da </span>
<span>So the electric field can be written as: </span>
<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>
<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
