Answer:
True
The escape speed from the Moon is much smaller than from Earth.
Explanation:
The escape speed is defined as:
(1)
Where G is the gravitational constant, M is the mass and r is the radius.
The mass of the Earth is 
and its radius is 
Then, replacing those values in equation 1 it is gotten.
For the case of the Moon:
Hence, the escape speed from the Moon is much smaller than from Earth.
Since it has a smaller mass and smaller radius compared to that from the Earth.
Your question kind of petered out there towards the end and you didn't specify
the terms, so I'll pick my own.
The "Hubble Constant" hasn't yet been pinned down precisely, so let's pick a
round number that's in the neighborhood of the last 20 years of measurements:
<em>70 km per second per megaparsec</em>.
We'll also need to know that 1 parsec = about 3.262 light years.
So the speed of your receding galaxy is
(Distance in LY) x (1 megaparsec / 3,262,000 LY) x (70 km/sec-mpsc) =
(150 million) x (1 / 3,262,000) x (70 km/sec) =
<em>3,219 km/sec </em>in the direction away from us (rounded)
When we swim we apply force and push the water backward with the help of our hands. In response, The water pushes us forward with an equal force. Thus, in order to move forward and swim, the swimmer lushes the water backward. Newton's 3rd law of motion
