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Vera_Pavlovna [14]
3 years ago
12

During a solvent extraction, a student lost track of which layer was the aqueous layer and which layer was the organic layer. Wh

at simple, non-destructive test could be used to determine which layer is which?
a. add a little distilled water to see which layer the water adds to

b. obtain a sample of the solution in the seperatory funnel and ultilize IR

c. ask the instructor if you can perform a supercritical extraction of the sample

c. obtain a sample of solution in seperatory funnel and utilize infrared spectroscopy (IR).
Chemistry
2 answers:
KatRina [158]3 years ago
4 0

Answer:

a. add a little distilled water to see which layer the water adds to

Explanation:

The problem tells us to keep in mind two major aspects of the test: It has to be <em>simple</em>, as well as <em>non-destructive</em>:

  • Adding distilled water can be made in under a minute, without requiring specialized laboratory equipment, unlike IR.
  • It is also non-destructive, because the contents on either layer won't change due to the added distilled water.
victus00 [196]3 years ago
4 0
A. add a little-distilled water to see which layer the water adds to

depending density of organic solvent-water layer can be top or bottom when we add little water you can absorb water addition or repulsion which helps to identify water layer
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Greeley [361]

Answer:

0.444 mol/L

Explanation:

First step is to find the number of moles of oxalic acid.

n(oxalic acid) = \frac{0.5g}{90.03 g/mol} = 5.5537*10^{-3} mol\\

Now use the molar ratio to find how many moles of NaOH would be required to neutralize 5.5537*10^{-3} mol\\ of oxalic acid.

n(oxalic acid): n(potassium hydroxide)

         1           :            2                  (we get this from the balanced equation)

5.5537*10^{-3} mol\\ : x

x = 0.0111 mol

Now to calculate what concentration of KOH that would be in 25 mL of water:

c = \frac{number of moles}{volume} = \frac{0.0111}{0.025} = 0.444 mol/L

5 0
4 years ago
An aqueous solution contains 32.7% KCl (wt/wt%). what is the mole fraction of KCl in the solution
inna [77]

The mole fraction of KCl in the solution is 0.1051

calculation

mole fraction of KCl in solution = moles of KCl / total number of moles(moles of KCl +moles of H2O)

moles=mass/molar mass

mass of KCl=32.7g

molar mass of KCl= 39 +35.5

moles of KCl is therefore= 32.7g/74.5 g/mol=0.439 moles

find the moles of H2O= mass of H2O/molar mass

mass of H2O=100-32.7=67.3g

molar mass of H2O=( 1 x2) +16=18 g/mol

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total moles=3.739+0.439=4.178 moles

mole fraction is therefore=0.439/4.178=0.1051

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3 years ago
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Can someone help on this?
AlexFokin [52]

Answer:

Igneous=B

Sedimentary=C

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8 0
4 years ago
Show the difference in the reactivity of Na,Ca,Mg,Al,Fe,Cu with H2O
Vesnalui [34]

Answer:

Explanation:

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2 Na+2H2O....................2NAOH + H2

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Mg react with water and form Magnesium hydroxide

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