Answer:
55738.539 Pa
Explanation:
Gvien:
The mass of the man = 73 kg
Mass of the chair = 7.4 kg
radius of the leg of the chair = 1.5 cm = 0.015 m
Now,
the force of gravity due to both the masses, F = (73+7.4) kg x 9.8 = 787.92 N
Also,
Pressure = force / area
Area of a circle of leg = πr² = π x 0.015² = 7.068 x10⁻⁴ m2
Now,
there are 2 legs so the force will be divided evenly in each leg
thus,
F' =
Hence, the pressure on each leg will be
Pressure =
Here is your answer
Velocity of car= 5 m/s
Time= 10 secs
We know that
Displacement = Velocity × time
So,
d= v×t= 5×10 m= 50 m
HOPE IT IS USEFUL
Answer:
v=20m/S
p=-37.5kPa
Explanation:
Hello! This exercise should be resolved in the next two steps
1. Using the continuity equation that indicates that the flow entering the nozzle must be the same as the output, remember that the flow equation consists in multiplying the area by the speed
Q=VA
for he exitt
Q=flow=5m^3/s
A=area=0.25m^2
V=Speed
solving for V
velocity at the exit=20m/s
for entry
2.
To find the pressure we use the Bernoulli equation that states that the flow energy is conserved.
where
P=presure
α=9.810KN/m^3 specific weight for water
V=speed
g=gravity
solving for P1
the pressure at exit is -37.5kPa
I guess technically it does.
But the only reason I know of that it should is the relativistic increase
of mass with speed ... that's why we never notice the increase at
everyday speeds.
The effect gets larger at higher speeds. For example, if the car is
cruising through the neighborhood at 6.71 million miles per hour
(1% the speed of light), then its mass, and therefore its weight,
is 0.005% more than when it's sitting still at a red light.
Now, if the driver were to put the pedal to the metal and open 'er up
to 10% the speed of light, then the car's mass (and the driver's mass
too) would increase to a whopping 0.5% more than its 'rest mass'.
So you would definitely have to say that the vehicle does get heavier
as it speeds up.
Answer:
4135 kgm/s
Explanation:
From the question,
Change in momentum (I) = mass (m) × change in velocity (Δv)
I = mΔv............................................ Equation 1
I = m(v₂-v₁)...................... Equation 2
Given: m = 827 kg, v₂ = 12 m/s, v₁ = 7 m/s
Substitute these values into equation 2
I = 827(12-7)
I = 827(5)
I = 4135 kgm/s