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maks197457 [2]
3 years ago
12

What can be used to relieve stress in a weld.

Engineering
2 answers:
Mekhanik [1.2K]3 years ago
7 0

Answer:

Streamline Stress Relief. "Over the years welders have perfected techniques to relieve stress and minimize distortion: preheating in an oven or with a torch, using heat blankets, and when necessary sending parts to an oven for postweld heat treatment.

Explanation:

Please mark me brainliest

satela [25.4K]3 years ago
3 0
Yes , of course you can
You might be interested in
Pam Jones worked for 41 years at the same company and had positive performance ratings and personnel records. She needed a calcu
UNO [17]

Answer:

a) The key issues are the sue for libel and the evidence.

b) I would make a deal with her and implement a security program in the company.

Explanation:

The main issue in this case is that Pam Jones sued the company for libel, and the company remains in a position in which it has to prove that the internal investigation followed the right steps and indeed, the proves reflected that she was guilty and the fact that she got fired was correct.

The important here is exactly that the theft can be proved.

As an HR Director, I would give the correct proves in order to win the case, and if that is impossible, because of the tools and evidence, I would make a deal with her where both parts can be adequate to the problem.

She can´t be working again in the company but she can get financed according to her working years; also I would use this case as a growing opportunity by implementing new security methods that give more confidence between the company and its employees.

5 0
3 years ago
Find the largest number. The process of finding the maximum value (i.e., the largest of a group of values) is used frequently in
salantis [7]

Answer:

See Explanation

Explanation:

Required

- Pseudocode to determine the largest of 10 numbers

- C# program to determine the largest of 10 numbers

The pseudocode and program makes use of a 1 dimensional array to accept input for the 10 numbers;

The largest of the 10 numbers is then saved in variable Largest and printed afterwards.

Pseudocode (Number lines are used for indentation to illustrate the program flow)

1. Start:

2. Declare Number as 1 dimensional array of 10 integers

3. Initialize: counter = 0

4. Do:

4.1 Display “Enter Number ”+(counter + 1)

4.2 Accept input for Number[counter]

4.3 While counter < 10

5. Initialize: Largest = Number[0]

6. Loop: i = 0 to 10

6.1 if Largest < Number[i] Then

6.2 Largest = Number[i]

6.3 End Loop:

7. Display “The largest input is “+Largest

8. Stop

C# Program (Console)

Comments are used for explanatory purpose

using System;

namespace ConsoleApplication1

{

   class Program

   {

       static void Main(string[] args)

       {

           int[] Number = new int[10];  // Declare array of 10 elements

           //Accept Input

           int counter = 0;

           while(counter<10)

           {

               Console.WriteLine("Enter Number " + (counter + 1)+": ");

               string var = Console.ReadLine();

               Number[counter] = Convert.ToInt32(var);

               counter++;                  

           }

           //Initialize largest to first element of the array

           int Largest = Number[0];

           //Determine Largest

           for(int i=0;i<10;i++)

           {

               if(Largest < Number[i])

               {

                   Largest = Number[i];

               }

           }

           //Print Largest

           Console.WriteLine("The largest input is "+ Largest);

           Console.ReadLine();

       }

   }

}

8 0
3 years ago
A simple formula to estimate the upward velocity of a rocket (neglecting the aerodynamic drag) is:
Bingel [31]

Answer:

Test code:

>>u=10;

>>g=9.8;

>>q=100;

>>m0=100;

>>vstar=10;

>>tstar=fzero_rocket_example(u, g, q, m0, vstar)

Explanation:

See attached image

5 0
3 years ago
A cylindrical buoy is 2m in diameter and 2.5m long and weight 22kN . The specific weight of sea water is 10.25kN/m^3 . (I) Show
aleksandrvk [35]

Answer:

GM

So the bouy does not float with its axis vertical

Explanation:

From the question we are told that:

Diameter d=2m

Length l=2.5m

Weight W=22kN

Specific weight of sea water \mu= 10.25kN/m^3

Generally the equation for weight of cylinder is mathematically given by

Weight of cylinder = buoyancy Force

W=(pwg)Vd

Where

V_d=\pi/4(d)^2y

Therefore

22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m

Therefore

Center of Bouyance B

B=\frac{y}{2}=0.26m\\\\B=0.75

Center of Gravity

G=\frac{I.B}{2}=2.6m

Generally the equation for\BM is mathematically given by

BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\

Therefore

BG=2.6-0.476\\\\BG=0.64m

Therefore

GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\

Therefore

GM

So the bouy does not float with its axis vertical

4 0
3 years ago
How many parts (screws and bolts included) does the average car have?
Leokris [45]
A single car has about 30,000 parts, counting every part down to the smallest screws
5 0
3 years ago
Read 2 more answers
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