Answer:
Point force (Qp) = 704 kn/m²
Explanation:
Given:
length = 19 m
Width = 0.5 m
fs = 4
Vicinity of the pile = 25
Find:
Point force (Qp)
Computation:
Point force (Qp) = fs²(l+v)
Point force (Qp) = 4²(25+19)
Point force (Qp) = 16(44)
Point force (Qp) = 704 kn/m²
Explanation:
what are the options for this question?
Answer:
V = 6.33 m/s
Explanation:
Given:
- The length of the wire L = 0.02 m
- The diameter of the wire D = 0.0005 m
- The calibration expression V = 0.0000625*h^2
- Environment temperature T_inf = 298 K
- Surface temperature T_s = 348 K
- The voltage drop dV = 5 V
- The electric current I = 0.1 A
Find:
- the velocity of Air
Solution:
- Calculate the surface area of the wire:
A = pi*D*L
A = pi*(0.0005)*(0.02) = 0.00003142 m^2
- The rate of energy in the wire P:
P = I*dV = 0.1*5 = 0.5 W
- Apply Newton's Law of Cooling:
P = h*A*(T_s - T_inf)
h = P /A*(T_s - T_inf)
Plug in the values:
h= 0.5/ 0.00003142*(348 - 298)
h = 318.27 W /m^2K
- Using the calibration relationship given, compute the velocity of air:
V = 6.25*10^-5 * h^2
V = 6.25*10^-5 * (318.27)^2
V = 6.33 m/s
Answer:
nah none of those i would get a tesla, mclaren, corvette, or even a toyota camery or tundra!
Explanation:
my dads is really big into cars and stuuf so i learn a little lol! hope it helps! thanks for the points by the way!
