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3 years ago

AA

Engineering

1 answer:

Whitepunk [10]3 years ago

8 0

Answer:

B. food safety and quality assurance manager

Explanation:

PLATO

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If the total energy change of an system during a process is 15.5 kJ, its change in kinetic energy is -3.5 kJ, and its potential

drek231 [11]

Answer:

The change in specific internal energy is 3.5 kj.

Explanation:

Step1

Given:

Total change in energy is 15.5 kj.

Change in kinetic energy is –3.5 kj.

Change in potential energy is 0 kj.

Mass is 5.4 kg.

Step2

Calculation:

Change in internal energy is calculated as follows:

$\bigtriangleup E=\bigtriangleup KE+\bigtriangleup PE+\bigtriangleup U$ $15.5=-3.5+0+\bigtriangleup U$

$\bigtriangleup U=19$ kj.

Step3

Specific internal energy is calculated as follows:

$\bigtriangleup u=\frac{\bigtriangleup U}{m}$

$\bigtriangleup u=\frac{19}{5.4}$

$\bigtriangleup u=3.5$ kj/kg.

Thus, the change in specific internal energy is 3.5 kj/kg.

7 0

4 years ago

A shaft 70 mm in diameter is being pushed at a speed of 400 mm/s through a bearing sleeve 70.2 mm in diameter and 250 mm long. T

Allushta [10]

Answer:

F=989.6 N

Explanation:

Given that

Diameter of shaft = 70 mm

Diameter of bearing sleeve =70.2 mm

So clearance h=0.1 mm

Speed V= 400 mm/s

Length of shaft = 250 mm

$\nu =0.005\ \frac{m^2}{s}\ , \rho=900\ \frac{kg}{m^3}$

We know that

$\mu =\rho\times\nu$

μ= 900 x 0.005 Pa-s

μ= 4.5 Pa-s

As we know that

From Newton's law of viscosity ,the shear stress given as follows

$\tau =\mu \dfrac{dU}{dy}$

We also know that

Force = shear stress x area

Now by putting the values

$\tau =4.5\times \dfrac{400}{0.1}$

$\tau=18,000 Pa$

So force

F= 18,000 x π x 0.07 x 0.25

F=988.6 N

6 0

3 years ago

Al of the following are common automotive network configurations EXCEPT:

qwelly [4]

Answer:

Option D

triangle series

Explanation:

Some of the common automotive network configurations include looped series configuration and star parallel. Moreover, bussed parallel network configuration is also used in automotive. However, there's no any network configuration called triangle series.

4 0

3 years ago

Please calculate the energy stored in a flying wheel. The steel flying wheel is 10 metric tons, in adiameter of 10m, and it rota

Liono4ka [1.6K]

Answer:

685.38 MJ

Explanation:

Given that:

mass = 10 tons = 1.0 × 10 ⁴ kg

diameter D = 10 m

radius R = 5 m

speed N = 1000 rpm