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In ΔOPQ, p = 4.8 cm, o = 4.7 cm and ∠O=69°. Find all possible values of ∠P, to the nearest 10th of a degree.
1 answer:
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9514 1404 393
Answer:
y = -3x^2 -9x +30
Step-by-step explanation:
When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...
f(x) = (x +5)(x -2)
At the point x=3, the value of this product is ...
f(3) = (3 +5)(3 -2) = (8)(1) = 8
In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...
y = -3(x +5)(x -2)
y = -3x^2 -9x +30 . . . . . standard form
