A 165 N object is supported by three cables(T1, T2 and T3), of which T1 and T2 are making angles θ1 = 52o and θ2 = 39o as shown
in Figure.
Here T3 = 165 N, calculate the tensions T1 and T2.
1
(a) Tension in string 1, T1 (in Newton) =
Answer for part 1
(b) Tension in string 2, T2 (in Newton) =
Answer for part 2
Hhgeppp plzzz
Here T3 = 165 N, calculate the tensions T1 and T2.
1
(a) Tension in string 1, T1 (in Newton) =
Answer for part 1
(b) Tension in string 2, T2 (in Newton) =
Answer for part 2
Hhgeppp plzzz
1 answer:
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Answer:
i) The period of the particle is 0.3 seconds
ii) The angular velocity is approximately 20.94 rad/s
iii) The linear velocity is approximately 1.047 m/s
iv) The centripetal acceleration is approximately 6.98 m/s²
Explanation:
The given parameters are;
The number of revolution of the particle, n = 800 revolution
The time it takes the particle to make 800 revolutions = 4 minutes
The dimension of the circle = 5 cm = 0.05 m
Given that the dimension of the circle is the radius of the circle, we have;
i) The period of the particle, T = The time to complete one revolution
T = 1/(The number of revolutions per second)
∴ T = 1/(800 rev/(4 min × 60 s/min)) = 3/10 s
The period, T = 3/10 seconds = 0.3 seconds
ii) The angular velocity, ω = Angle covered/(Time)
800 revolutions in 4 minutes = Angle of (800 × 2·π) in 4 minutes
∴ ω = (800 × 2·π)/(4 × 60) = 20·π/3
The angular velocity, ω = 20·π/3 rad/s ≈ 20.94 rad/s
iii) The linear velocity, v = r × ω
∴ The linear velocity, v = 0.05 m × 20·π/3 rad/s = π/3 m/s ≈ 1.047 m/s
iv) The centripetal acceleration, = v²/r
∴ The centripetal acceleration, = (π/3)²/(0.05) = 20·π/9
The centripetal acceleration, = 20·π/9 m/s² ≈ 6.98 m/s²
Explanation:
Formula to calculate electric field because of the plate is as follows.
E =
=
=
Now, we will consider that equilibrium of forces are present there. So,
ma = qE
a =
=
According to the third equation of motion,
or, d =
=
= 0.254 m
Thus, we can conclude that the proton will travel 0.254 m before reaching its turning point.