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Tems11 [23]
3 years ago
9

A gardener decides to use only part of their garden in the spring. What will most likely happen first in the unused part of the

garden?
Chemistry
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

Growth of weeds and grasses

Explanation:

The part of the garden, probably left to rest by the Gardner, would start experiencing a legion of invasive plants. Giant weeds and grasses could be seen, and brambles and tree seedlings could also sneak in.  

Some Gardeners would recommend the use of herbicides to restore order to an abandoned garden even though certain scientists are of the opinion that chemicals may not offer a sound solution to the problem.  

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The HNO3 is considered to be a Bronsted - Lowry acid, when this substance 'HNO3', will donate a proton, then it will form another substance. It will form two substances when the proton is donated in the water molecule. The two substances that will be formed is a nitrate iron and a hydronium ion.
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Question 1 (1 point)
Strike441 [17]

Answer:

Scientist used models to explain and predict the behavior of real object or system

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What main factor determines the path a star will take during its life cycle
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4 years ago
The addition of hydrochloric acid to a silver nitrate solution precipitates silver chloride according to the reaction:
Nimfa-mama [501]

Answer:

Enthalpy change for the reaction is -67716 J/mol.

Explanation:

Number of moles of AgNO_{3} in 50.0 mL of 0.100 M of AgNO_{3}

= Number of moles of HCl in 50.0 mL of 0.100 M of HCl

= \frac{0.100}{1000}\times 50.0 moles

= 0.00500 moles

According to balanced equation, 1 mol of AgNO_{3} reacts with 1 mol of HCl to form 1 mol of AgCl.

So, 0.00500 moles of AgNO_{3} react with 0.00500 moles of HCl to form 0.00500 moles of AgCl

Total volume of solution = (50.0+50.0) mL = 100.0 mL

So, mass of solution = (100.0\times 1.00) g = 100 g

Enthalpy change for the reaction = -(heat released during reaction)/(number of moles of AgCl formed)

= \frac{-m_{solution}\times C_{solution}\times \Delta T_{solution}}{0.00500mol}

= \frac{-100g\times 4.18\frac{J}{g.^{0}\textrm{C}}\times [24.21-23.40]^{0}\textrm{C}}{0.00500mol}

= -67716 J/mol

[m = mass, c = specific heat capacity, \Delta T = change in temperature and negative sign is included as it is an exothermic reaction]

4 0
3 years ago
What is the molarity of ZnCl, that forms when 20.0 g of zinc completely reacts with CuCl2, according to the following reaction?
laila [671]
1.61m :) use the photo below

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3 years ago
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