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3 years ago

Write a chemical equation showing how each behaves as an acid when dissoblbed in water.

Chemistry

1 answer:

nikdorinn [45]3 years ago

8 0

Answer:

a. H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)

b. NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)

Explanation:

According to Bronsted-Lowry acid-base theory,

An acid is a substance that donates a H⁺.

A base is a substance that accepts a H⁺.

a. When dissolved in water, H₂S behaves as an acid according to the following equation.

H₂S(aq) + H₂O(l) ⇄ HS⁻(aq) + H₃O⁺(aq)

b. When dissolved in water, NH₄⁺ behaves as an acid according to the following equation.

NH₄⁺(aq) + H₂O(l) ⇄ NH₃(aq) + H₃O⁺(aq)

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Answer:

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In order to find the amount of molecules of each of the options, we need to follow the following equation.

$molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}$

So, let´s get the number of molecules for each of the options.

$a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules$

$b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules$

$c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules$

$d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules$

$d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules$

the smalest number is in option a)

Best of luck.

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3 years ago

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Answer:

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