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3 years ago

Figure ABCD is a rhombus with point A (3,-1) what rule would rotate the figure 270 counterclockwise

Mathematics

2 answers:

Bas_tet [7]3 years ago

8 0

(x,y)-->(y,-x) should be the answer

n200080 [17]3 years ago

5 0

Answer: $(a,b)\rightarrow\ (-b, a)$ where (a,b) represents the coordinates for the pre-image and (-b,a) represents the coordinates for image.

Step-by-step explanation:

After rotating a figure 270° counterclockwise, then the x-coordinate interchanges with negative value of y-coordinate and y-coordinate interchanges with the value of -x coordinate.

The rule for rotating the figure 270° counterclockwise is given by :-

$(a,b)\rightarrow\ (-b, a)$

where (a,b) represents the coordinates for the pre-image and (-b,a) represents the coordinates for image.

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3 years ago

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makvit [3.9K]

Answer:

A <u>rational number</u> is a number that can be expressed as a fraction (the ratio of two integers).

<u>Integer</u>: A whole number that can be positive, negative, or zero.

To calculate if each radical can be expressed as a rational number, convert the decimals into rational numbers, then simplify:

$\sqrt{121}=\sqrt{11^2}=11=\dfrac{11}{1} \quad \leftarrow \textsf{rational}$

$\sqrt{12.1}=\sqrt{\dfrac{1210}{100}}=\dfrac{\sqrt{1210}}{\sqrt{100}}=\dfrac{\sqrt{121\cdot 10}}{10}=\dfrac{\sqrt{121}\sqrt{10}}{10}=\dfrac{11\sqrt{10}}{10} \leftarrow \textsf{not rational}$

$\sqrt{1.21}=\sqrt{\dfrac{121}{100}}=\dfrac{\sqrt{121}}{\sqrt{100}}=\dfrac{\sqrt{11^2}}{\sqrt{10^2}}=\dfrac{11}{10} \leftarrow \textsf{rational}$

$\sqrt{0.0121}=\sqrt{\dfrac{121}{10000}}=\dfrac{\sqrt{121}}{\sqrt{10000}}=\dfrac{\sqrt{11^2}}{\sqrt{100^2}}=\dfrac{11}{100} \leftarrow \textsf{rational}$

Therefore, $\sf \sqrt{12.1}$ is not a rational number.

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1 year ago