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Vlad [161]
3 years ago
5

True or false The mass of an electron is about equal to the mass of a proton.

Chemistry
1 answer:
pogonyaev3 years ago
7 0
That is false (please mark me brainliest)
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What was the weight percent of water in the hydrate before heating?
DedPeter [7]
Data:

weight of water before heating = 0.349

weight of hydrate before heateing = 2.107

Formula:

Weight percent of water = [ (weight of water) / (weight of the hydrate) ] * 100

Solution:

Weight percent of water = [ 0.349 / 2.107] * 100 ≈ 16.6 %

Answer: 16.6%
3 0
3 years ago
Hot, molten rock deep below Earth’s surface is called lava mantle rock parent rock magma
Rashid [163]

Answer:

I think it is Magma

6 0
3 years ago
A scooter maintains a pace of 1.45 minutes per mile, with fuel economy of 85 miles per gallon. How many seconds can it travel on
vlada-n [284]

Answer:

281s

Explanation:

Given parameters:

Speed of the scooter  = 1.45min per mile

Fuel economy of engine  = 85miles per gallon

Quantity of fuel  = 145mL

Unknown:

Time of travel with the volume of fuel given  = ?

Solution:

To solve this problem, we need to find the distance the fuel will last.

 Rate of fuel consumption by the engine  = 85miles per gallon

Convert 145mL to gallons;

                3785.41mL  = 1 gallon

               145mL will therefore give \frac{145}{3785.41}    = 0.038gallons

So;

   Distance covered  = 85miles per gallon  x 0.038gallons  = 3.23miles

From;

             Rate of travel  = \frac{time }{distance}  

       Time  = rate of travel x distance  = 1.45 minutes per mile x  3.23miles

     Time  = 4.7min

             1 min  = 60s

            4.7min  = 4.7 x 60 = 281s

6 0
3 years ago
In order to prepare 50.0 mL of 0.100 M NaOH you will add _____ mL of 1.00 M NaOH to _____ mL of water
FinnZ [79.3K]

The question requires us to complete the sentence regarding the preparation of a more dilute NaOH solution (0.100 M, 50.0 mL) from a more concentrated NaOH solution (1.00 M).

Analyzing the blank spaces that we need to fill in the sentence, we can see that we must provide the volume of the more concentrated solution and the volume of water necessary to prepare the solution.

We can use the following equation to calculate the volume of more concentrated solution required:

\begin{gathered} C_1\times V_1=C_2\times V_2 \\ V_1=\frac{C_2\times V_2}{C_1} \end{gathered}

where C1 is the concentration of the initial solution (C1 = 1.00 M), V1 is the volume required of the inital solution (that we'll calculate), C2 is the concentration of the final solution (C2 = 0.100 M) and V2 is the volume of the final solution (V2 = 50.0 mL).

Applying the values given by the question to the equation above, we'll have:

\begin{gathered} V_1=\frac{C_2\times V_2}{C_1} \\ V_1=\frac{0.100M_{}\times50.0mL_{}}{1.00M_{}}=5.00mL \end{gathered}

Thus, we would need 5.00 mL of the more concentrated solution.

Since the volume of the final solution is 50.0 mL and it corresponds to the volume of initial solution + volume of water, we can calculate the volume of water necessary as:

\begin{gathered} \text{final volume = volume of initial solution + volume of water} \\ 50.0mL=5.00mL\text{ + volume of water} \\ \text{volume of water = 45.0 mL} \end{gathered}

Thus, we would need 45.0 mL of water to prepare the solution.

Therefore, we can complete the sentence given as:

<em>"In order to prepare 50.0 mL of 0.100 M NaOH you will add </em>5.00 mL<em> of 1.00 M NaOH to </em>45.0 mL<em> of water"</em>

5 0
1 year ago
A certain object has a volume of 25.0 mL and a mass of 100 g. What is the density of the object?
svetlana [45]
Density = mass/volume

Since there was no condition of unit attached to the question...

Density = 100g/25.0ml

Density = 4g/mL.......
3 0
3 years ago
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