Answer:
The amount of NO₂ that can be produced 8.533 g
Explanation:
According to question
2 NO(g) + O₂(g) → 2 NO₂(g)
Given
Moles of nitrogen monoxide = 0.377
Moles of oxygen = 0.278
Since 'NO' is the limiting reagent according to this ratio.
According to equation
2 moles NO reacts to form 2 moles NO₂
So, 0.1855 moles NO give = 0.1855 moles of NO₂
Mass of 1 mole NO₂ = 46 g/mole
Mass of 0.1855 moles = 46 x 0.1855 = 8.533 g
Notice q=3/2, is half of the original q = 3(<span>1/2</span>)<span>t/28.8
your welcome
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Answer:
5.5 L
Explanation:
First we <u>convert 10 g of propane gas</u> (C₃H₈) to moles, using its <em>molar mass</em>:
- 10 g ÷ 44 g/mol = 0.23 mol
Then we <u>use the PV=nRT formula</u>, where:
- P = 1 atm & T = 293 K (This are normal conditions of T and P)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
1 atm * V = 0.23 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 293 K
I think Geothermal but I’m not 100% sure
Answer:
Mean rate of reaction produced = 0.533 g/sec (approx.)
Explanation:
Given:
Reaction produced = 1.6 gram
Time taken = 30 sec
Find:
Mean rate of reaction produced
Computation:
Mean rate of reaction produced = Reaction produced / Time taken
Mean rate of reaction produced = 1.6 / 30
Mean rate of reaction produced = 0.533 g/sec (approx.)
