Answer:
1) acetylide
2) enol
3) aldehydes
4) tautomers
5) alkynes
6) Hydroboration
7) Keto
8) methyl ketones
Explanation:
Acetylide anions (R-C≡C^-) is a strong nucleophile. Being a strong nucleophile, we can use it to open up an epoxide ring by SN2 mechanism. The attack of the acetylide ion occurs from the backside of the epoxide ring. It must attack at the less substituted side of the epoxide.
Oxomercuration of alkynes and hydroboration of alkynes are similar reactions in that they both yield carbonyl compounds that often exhibit keto-enol tautomerism.
The equilibrium position may lie towards the Keto form of the compound. Usually, if terminal alkynes are used, the product of the reaction is a methyl ketone.
Answer:
21.3 g of CaCl₂ are produced in this reaction
Explanation:
Reaction is this:
CaCO₃ + 2HCl → CaCl₂ + H₂CO₃
Molar mass salt : 100.08 g/m
Molar mass acid: 36.45 g/m
We have 28 g / 100.08 g/m = 0.279 moles of CaCO₃
We have 14 g / 36.45 g/m = 0.384 moles of HCl
Ratio is 1:2, so 0.279 moles of salt will need the double of moles of acid.
0.279 . 2 = 0.558 moles of acid needed. (I have only 0.384 moles, so the acid is the limiting reactant)
0.384 moles of HCl produce the half of moles of CaCl₂ (This ratio is 1:2) --> 0.192 moles
Molar mass of CaCl₂ = 110.98 g/m
Mol . molar mass = mass → 0.192 m . 110.98 g/m = 21.3 g
The lowest time = salt water . ocean water freezes at lower temperatures than fresh waters.
Answer:
3.6 gallons are equal to 56 cups
