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rusak2 [61]
4 years ago
13

More than 5 points and will pick brainliest answer plus I will give thanks❗️❕❗️(Don’t answer if you don’t know the answer)

Physics
1 answer:
Setler79 [48]4 years ago
5 0
The answer is 2 and 3 because light bulbs dont produce uv rays and uv rays are very dangerous to people.
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The potential difference between points A and B in an electric
Flauer [41]

Answer:

i hope  the answear is D becuase  went over this long time ago when i was like you

Explanation:

3 0
3 years ago
Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

I_3 = 0.920 A

6 0
4 years ago
A cube measures 3 cm on each side and has a mass of 25 g. What is its density.
Snowcat [4.5K]

Answer:

The density is:   0.926 \,\frac{g}{cm^3}

Explanation:

Recall that density is defined as the quotient of the object's mass divided by volume. So, we calculate the volume of the 3 cm side cube:

Vol = (3 \,cm)^3 = 27 \,\,cm^3

then the density becomes:

density=\frac{mass}{Vol} =\frac{25}{27} \,\frac{g}{cm^3} \approx 0.926 \,\frac{g}{cm^3}

7 0
4 years ago
you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh
inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

d_{x} =\frac{d}{sin\theta } =\frac{0.679}{1.116x10^{-4} } =6.084x10^{3} m=6.084km

7 0
4 years ago
A light shines up from the bottom of a fish pond.
likoan [24]
<span>For the question "A light shines up from the bottom of a fish pond. Which diagram shows the correct path of light as it leaves the water of the pond and hits the air?" The second diagram is the correct answer. Water has a higher refractive index than air so the ray of light passing from water to air will be refracted away from the normal (the vertical) towards the surface of the water.</span>
7 0
3 years ago
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