Answer:
8.25 V
Explanation:
We can ignore the 22Ω and 122Ω resistors at the bottom. Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.
The 2Ω resistor and the 44Ω resistor are in parallel. The equivalent resistance is:
1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω
This resistance is in series with the 12Ω resistor. The equivalent resistance is:
1.913Ω + 12Ω = 13.913Ω
This resistance is in parallel with the 24Ω resistor. The equivalent resistance is:
1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω
Finally, this resistance is in series with the 4Ω resistor. The equivalent resistance of the circuit is:
8.807Ω + 4Ω = 12.807Ω
The current through the battery is:
12 V / 12.807Ω = 0.937 A
The voltage drop across the 4Ω resistor is:
(0.937 A) (4Ω) = 3.75 V
So the voltage between the bottom nodes and the top nodes is:
12 V − 3.75 V = 8.25 V
Answer:
* angular momentum throughout the lar process is conserved throughout the entire process
* the angular velocity decreases as the radius of the pizza increases
Explanation:
The system formed by the masses is isolated so its angular momentum is conserved
initial instant, which throws the mass with angular velocity o and radius ro
L₀ = I w₀
final instant. When the mass has a radius r and an angular velocity w
L_f = I_f w
Lo = l_f
I₀ w₀ = I_f w_f
let's analyze this result
* angular momentum throughout the lar process is conserved throughout the entire process
* the angular velocity decreases as the radius of the pizza increases
This is because x is not an expanding part of the spring
The acceleration of the baseball is:
where
and
are the final and initial speed of the ball, and
is the time interval in which the force acted.
Replacing the numbers, we get
And at this point, we can use Newton's second law F=ma to find the value of the force of the pitching machine:
Answer:
V0=27.4 m/s; t=0.8 s
Explanation:
Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:
We solve for initial speed
Now, using the same expression we estimated time to first reach 18.5 m :
Second order equation with solutions
t1=0.8 s and t2=4.8 s
The first time corresponds to the first reach.