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Allushta [10]
4 years ago
14

What does botanist study? A. Boats B.Matter C. chemicals D. Plants

Chemistry
1 answer:
4vir4ik [10]4 years ago
8 0

What does botanist study?

\implies {\blue {\boxed {\boxed {\purple {\sf {D.\: Plants}}}}}}

\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆

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What is the charge of the nucleus ? Why ?
mars1129 [50]

Answer:

A nucleus is a positive charge

Explanation:

A nucleus is made up of protons and neutrons. Protons have a positive charge and neutrons have a neutral charge.

8 0
3 years ago
A piece of lead with a mass of 14.9 grams at a temperature of 92.5 degrees Celsius is dropped into an insulated container of wat
Vesna [10]

the specific heat of lead is

6 0
3 years ago
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What is the pH of a solution that contains 0.83M HCN (Ka = 4.9x10-10) and 0.64 M potassium cyanide?
oksian1 [2.3K]

Answer:

pH= 9.2

Explanation:

Henderson hasselbach equation

pKa= log Ka= log (4.9 x 10^-10)=9.3

pH=Pka+log \frac{[A-]}{[HA]}

pH=9.3+log \frac{[CN-]}{[HCN]}

pH=9.3+log \frac{[0.64 M]}{[0.83 M]}

pH= 9.2

5 0
3 years ago
Aqueous strontium sulfide and aqueous copper(II) sulfate
ryzh [129]

Answer: The reaction does occur.

Explanation: For the reaction of aqueous strontium sulfide and aqueous copper(II) sulfate, the reaction follows:

SrS(aq.)+CuSO_4(aq.)\rightarrow SrSO_4(aq.)+CuS(s)

This reaction is a type of precipitation reaction.

The precipitate formed is CuS which is black in color.

5 0
3 years ago
A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+
natima [27]

Answer:

A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.515 g/L at 0.745 atm .

(4x^2)x

Kc= -----------

(A-2x)^2

PV=nRT

n/v = P/RT = .745/(0.0821)(334+273) = .01495

To Find the initial molarity of NO2

(mol/L)(g/mol) + (mol/L)(g/mol) + (mol/L)(g/mol)= g/L

Thus:

46(A-2x) + 2x(30) + 32x = .515 g/L

46A-92x+60x+32x = .515

46A=.515

A=.01120 M

Using the total molarity found

(A-2x)+2x+x = .01495 M

A+x=.01495

Plug in A found into the above equation:

.01120+x = .01495

x=.00375

Now Plug A and x into the original Equilibrium Constant Expression:

(4x^2)x

Kc= -----------

(A-2x)^2

Kc = 0.000014

Explanation:

3 0
3 years ago
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