Look to be honest, I don't know how to work out the problem, but my teacher, and my says it takes 8 minutes for the Sun's light to reach
hope my answer works :)
For every 2 mole Mg we need 1 mole O2 ( based on the equation). since there is 4 mole Mg we need 2 mole O2. one mole O2 is 32 gram so 2 mole would be 64 grams.
Answer:
Explanation:
CH₃COOH(aq) + NaHCO₃(s) -> CO₂(g) + H₂O(l) + Na+(aq) + CH₃COO-(aq)
The equation is already balanced .
In the reaction acetic acid reacts with sodium bicarbonate to produce carbon dioxide gas , water and sodium acetate . Sodium acetate will be in ionic form ie in the form of Na⁺ ( sodium ion ) and CH₃COO ⁻ ion ( acetate ion ) .
This is an acid base neutralisation reaction . one mole of acetic acid reacts with one mole of sodium bicarbonate to produce one mole of carbon dioxide gas , one mole of water and one mole of sodium acetate in ionic form .
The answer is (9,11)
Midpoint formula: (x1 + x2)/2, (y1 + y2)/2, where (x1, y1) and (x2, y2) are the endpoints of the segment
<span>x-coordinate of midpoint = (x1 + x2)/2 </span>
<span>5 = (1 + x2)/2 </span>
<span>10 = 1 + x2 </span>
<span>9 = x2 </span>
<span>y-coordinate of midpoint = (y1 + y2)/2 </span>
<span>3 = (-5 + y2)/2 </span>
<span>6 = -5 + y2 </span>
<span>11 = y2 </span>
Answer:
4NH₃ + 5O₂ —> 4NO + 6H₂O
Explanation:
NH₃ + O₂ —> NO + H₂O
The above equation can be balance as follow:
NH₃ + O₂ —> NO + H₂O
There 3 atoms of H on the left side and 2 atoms on the right side. It can be balance by 4 in front of NH₃ and 6 in front of H₂O as shown below:
4NH₃ + O₂ —> NO + 6H₂O
There are 4 atoms of N on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NO as shown below:
4NH₃ + O₂ —> 4NO + 6H₂O
There are 2 atoms of O on the left side and a total of 10 atoms on the right side. It can be balance by putting 5 in front of O₂ as shown below:
4NH₃ + 5O₂ —> 4NO + 6H₂O
Thus, the equation is balanced.
