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mojhsa [17]
3 years ago
13

The church believes all of these except?

Chemistry
1 answer:
pav-90 [236]3 years ago
6 0
I believe it is still A with the current state of things, but there is talk in the church of reforming to allow women priests.
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A sample of the chiral molecule limonene is 79% enantiopure. what percentage of each enantiomer is present? what is the percent
Degger [83]

Answer :  The % of (+) limonene isomer = 79%


                The % of (-) limonene isomer = 0%


                The % of enantiomeric excess = 58%


Explanation :   Enantiomeric excess (ee) is the measurement of purity used for chiral substances.


Given,


% of pure limonene enantiomer = The % of (+) limonene isomer = 79%


Therefore, The % of (-) limonene isomer = 0%


Formula used :  

\%(+)\text{ isomer}=\frac{ee}{2}+50\%


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Now, put all the values in above formula, we get the value of enantiomeric excess (ee).


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            =\frac{79\%-50\%}{2}


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