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3 years ago

Need help with 6th grade math

Mathematics

1 answer:

Arada [10]3 years ago

7 0

1 kilogram of baking soda costs $4.5

Step-by-step explanation:

To solve this problem, we will follow the steps bellow:

Using proportion;

Let x be the cost of 1 kg of baking soda

kilogram = $ 2

1 kilogram = x

Cross - multiply

× x = $2 × 1

× x = $2

= $2

Multiply both-side of the equation by 9

× 9= $2 × 9

At the left-hand side of the equation 9 will cancel-out 9, hence our equation becomes

4x = $18

Divide both-side of the equation by 4

= $

x = $4.5

1 kilogram of baking soda costs $4.5

Step-by-step explanation:

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Simplify the following expression:<br> -8 (5b + 2) -7 ( b-5)

RUDIKE [14]

Answer:

-8(5b+2)-7(b-5)

first, use distributive property to get:

-40b-16-7b+35

then, use combine like terms to simplify:

-47b+19

that's your answer!

:)))))))))

3 0

3 years ago

Read 2 more answers

Evaluate 17 + 70/x when x = 14.

kipiarov [429]

Answer:

34.5

Step-by-step explanation:

17 + 70/x when x = 14.

substitute x for 14

17 + 70/4

17 + 17.5

34.5

5 0

3 years ago

PLEASE HELP!! brainliest if correct!!

Sonja [21]

Graph #1: No
Graph #2: Yes
Graph #3: No
Graph #4: No
Graph #5: No
Graph #6: Yes

Reasoning:

The vertical line test is a test that determines wether a graph is a function or a relation. The vertical line test shows that if you construct a vertical line through any point on the graph, then the vertical line should only intercept the graph once for it to be a function.

6 0

2 years ago

Can you guys check my work pls?

alex41 [277]

Hey number 8. Be super careful, less than always look at that it should be 5n-3

3 0

3 years ago

Which equation could represent a circle with a center located at (11,-5)

Anon25 [30]

The standard equation of a circle is:

$(x-h)^2-(y-k)^2=r^2$ where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.

$(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64$

The bolded part is your answer. Since the radius is not given, we can put any value.

6 0

3 years ago