The question is incomplete! The complete question along with answer and explanation is provided below.
Question:
A student bikes to school by traveling first 1.00 miles north, then 0.500 miles west and finally 0.200 miles south.
If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance db would the bird cover
Given Information:
distance towards north = dn = 1.00 mi
distance towards west = dw = 0.500 mi
distance towards south = ds = 0.200 mi
Required Information:
distance covered by bird = db = ?
Answer:
distance covered by bird = 0.94 miles
Explanation:
As you can see in the attached image, by applying the Pythagoras theorem,
db = √(dn - ds)² + dw²
db = √ (1.0 - 0.20)² + 0.50²
db = √ 0.80² + 0.50²
db = 0.94 miles
Therefore, the bird would cover a distance of 0.94 miles
Power is equal to work divided by time
Explanation:
Use Pythagorean theorem:
r² = x² + y²
r² = (-7.11 m)² + (-4.41 m)²
r = 8.37 m
Use trig to find the angle.
tan θ = y / x
tan θ = (-4.41 m) / (-7.11 m)
θ = 31.8° or 211.8°
Since x is negative and y is negative, the point is in the third quadrant, so θ = 211.8°.
Or, if we subtract 360°, θ = -148.2°.
Answer:
4.4.
Explanation:
Hello,
In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.
In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.
Regards-