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fredd [130]
3 years ago
8

Which event demonstrates electromagnetic waves transferring energy?

Physics
2 answers:
Licemer1 [7]3 years ago
6 0

Answer:

d

Explanation:

Citrus2011 [14]3 years ago
4 0

Answer:

Sun heating a car sitting in a parking lot

Explanation:

The sun heating a car sitting in a parking lot is an example of electromagnetic waves transferring energy.

  • Electromagnetic waves are produced from the vibration between electric and magnetic fields.
  • These waves can be propagated through vacuum with no particles inside of them.
  • The sun produces electromagnetic radiation through the process of nuclear fusion.
  • These radiations are used to warm the earth surface.
  • The sun heating a car sitting a parking lot is one vivid example.
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25 + 18-6-1.......​
Romashka [77]

Answer:36

Explanation:use a calculator?

8 0
4 years ago
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Consider an electrical transformer has 10 loops on its primary coil and 20 loops on its secondary coil. What is the voltage in t
Arlecino [84]

Answer:

240 V

Explanation:

number of turns in primary coil, Np = 10

Number of loops in secondary coil, Ns = 20

Voltage in primary coil, Vp = 120 V

Let the voltage in secondary coil is Vs.

So, Vs / Vp = Ns / Np

Vs / 120 = 20 / 10

Vs / 120  = 2

Vs = 240 V

Thus, the voltage in secondary coil is 240 Volt.

4 0
3 years ago
What is free fall? Explain it in brief.​
xxTIMURxx [149]
 · free fall is any motion of a body where gravity is the only forceacting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

3 0
3 years ago
It is desired to create a particle of mass 7920 MeV/c^2 in a head-on collision between a proton and an antiproton (each having a
Olegator [25]

Answer:

v=0.9714c

Explanation:

The kinetic energy possessed by  particles will be  

K.E=\frac{1}{2}Mc^2

where,

M is the mass of the particle (7920938.3 MeV/c²)

c is the speed of the light

Also,

energy of the proton particle = \frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}

where,

v is the velocity

m_p is the mass of the proton (938.3 MeV/c²)

since the energy is equal

thus,

\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{1}{2}Mc^2

or

1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2

substituting the values in the above equation, we get

1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2

or

v=0.9714c

Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>

5 0
3 years ago
When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini
valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0
4 years ago
Read 2 more answers
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