Answer:
1.2 s
Explanation:
We'll begin by calculating the length (i.e distance) of the ramp. This can be obtained by using pythagoras theory as illustrated below:
NOTE: Length of the ramp is the Hypothenus i.e the longest side.
Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:
s² = 4² + 3²
s² = 16 + 9
s² = 25
Take the square root of both side
s = √25
s = 5 m
Thus the length of the ramp is 5 m
Next, we shall determine the final velocity of the ball. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
v² = u² + 2as
v² = 3² + (2 × 2 × 5)
v² = 9 + 20
v² = 29
Take the square root of both side
v = √29
v = 5.39 m/s
Finally, we shall determine the time taken for the ball to reach the final position. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Final velocity (v) = 5.39 m/s
Time (t) =?
v = u + at
5.39 = 3 + 2t
Collect like terms
5.39 – 3 = 2t
2.39 = 2t
Divide both side by 2
t = 2.39 / 2
t = 1.2 s
Thus, it will take 1.2 s for the ball to get to the final position.
Answer:
P =18760.5 Pa
Explanation:
Given that
Volume ,V= 0.0434 m³
Mass ,m= 4.19 g = 0.00419 kg
T= 417 K
If we assume that water vapor is behaving like a ideal gas ,then we can use ideal gas equation
Ideal gas equation P V = m R T
p=Pressure ,V = Volume ,m =mass
T=Temperature ,R=Universal gas constant
Now by putting the values
P V = m R T
For water R= 0.466 KJ/kgK
P x 0.0434 = 0.00419 x 0.466 x 417
P =18.7605 KPa
P =18760.5 Pa
Therefore the answer is 18760.5 Pa
Equilibrium is when the opposing forces or influences are balanced. So it would be E!
Answer:
215mph
Explanation:
multiply 112milws by 2 and multiple that by seven, then divide it by two
