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torisob [31]
3 years ago
14

The results of an independent-samples t test were t(19) = 4.02, p < 0.05. In this example,

Mathematics
1 answer:
madam [21]3 years ago
8 0
T(1982738)x44-88^5517t
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4 years ago
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One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Which equation is equivalent to sqrt x +11=15
Bas_tet [7]

Answer:

x=16

Step-by-step explanation:

We are given that

\sqrtx+11=15

we have to solve this equation for x

in order to do that we need to isolate x first

hence

subtracting 11 from both sides we get

\sqrtx+11-11=15-11

\sqrtx=4

Now we square on both sides we get

(\sqrtx)^2=4^2

x=4 \times 4

x=16

hence x =16

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3 years ago
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Descending order...largest to smallest
the largest one is the one with the biggest exponent
so the first term is : 7z^4
3 0
3 years ago
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