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Zepler [3.9K]
2 years ago
6

20 ML of a gas at 200 K is heated until the new volume is 55ML what is the final temperature of the gas

Chemistry
1 answer:
MrRa [10]2 years ago
8 0

Answer:

T2 = 550K

Explanation:

From Charles law;

V1/T1 = V2/T2

Where;

V1 is initial volume

V2 is final volume

T1 is initial temperature

T2 is final temperature

We are given;

V1 = 20 mL

V2 = 55 mL

T1 = 200 K

Thus from V1/T1 = V2/T2, making T2 the subject;

T2 = (V2 × T1)/V1

T2 = (55 × 200)/20

T2 = 550K

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Answer:

1. Orbital diagram

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

2. Quantum numbers

  • <em>n </em>= 2,
  • <em>l</em> = 1,
  • m_{l} = 0,
  • m_{s} = +1/2

Explanation:

The fill in rule is:

  • Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
  • Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
  • Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

The quantum number of an electron consists of four number:

  • <em>n </em>(shell number, - 1, 2, 3...)
  • <em>l</em> (subshell number or  orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
  • m_{l} (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
  • m_{s} (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

  • <em>n </em>= 2, shell number 2,
  • <em>l</em> = 1, subshell or orbital <em>p,</em>
  • m_{l} = 0, 2nd "box" in the range -1, 0, 1
  • m_{s} = +1/2, single electron always has +1/2
3 0
3 years ago
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