Not sure about 2 or 3 but I believe that for number 1 is B or claim 2!!
Answer:
it's is math that you can answer with your sister and your mother
3.4 molecules is in 127 grams of iodine
Answer:
Explanation:
im not 100% sure but maybe d
From the information provided in the question, the mass of NiCl2 required is 0.23 g.
NiCl2(aq) + 2AgNO3(aq) -------> 2AgCl(s) + Ni(NO3)2(aq)
Number of moles of AgCl= Mass/molar mass
Molar mass of AgCl= 143 g/mol
Substituting values;
Number of moles = 503 × 10^-3g/143 g/mol= 0.00352 moles
Since 1 mole NiCl2 precipitates 2 moles of AgCl
x moles of NiCl2 precipitates 0.00352 moles of AgCl
x = 1 mole × 0.00352 moles/2 moles
x = 0.00176 moles of NiCl2
Mass of NiCl2= 0.00176 moles × 130 g/mol = 0.23 g
Learn more: brainly.com/question/2510654
