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3 years ago

20 ML of a gas at 200 K is heated until the new volume is 55ML what is the final temperature of the gas

Chemistry

1 answer:

MrRa [10]3 years ago

8 0

Answer:

T2 = 550K

Explanation:

From Charles law;

V1/T1 = V2/T2

Where;

V1 is initial volume

V2 is final volume

T1 is initial temperature

T2 is final temperature

We are given;

V1 = 20 mL

V2 = 55 mL

T1 = 200 K

Thus from V1/T1 = V2/T2, making T2 the subject;

T2 = (V2 × T1)/V1

T2 = (55 × 200)/20

T2 = 550K

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solubility of cu(oh)2 is 2.42 x 10-3 mol/l. calculate ksp and in which direction the reaction is spontaneous if δgº

Simora [160]

Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.

Chemical reaction (dissociation) of copper(II) hydroxide in water:

Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).

Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².

[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions

[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l

[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions

Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²

Ksp = 4.9 x 10-8

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

Solubility of the compound depends on the temperature of the solution and the structure of that compound.

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7 0

2 years ago

A solution is prepared by dissolving 215 grams of methanol, ch3oh, in 1000. grams of water. what is the freezing point of this s

Leya [2.2K]

Answer : The freezing point of the solution is, 260.503 K

Solution : Given,

Mass of methanol (solute) = 215 g

Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)

Freezing depression constant = $1.86^oC/m=1.86Kkg/mole$

Formula used :

$\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}$

where,

$T^o_f$ = freezing point of water = $100^oC=273K$

$T_f$ = freezing point of solution

$K_f$ = freezing point constant

$w_{solute}$ = mass of solute

$w_{solvent}$ = mass of solvent

$M_{solute}$ = molar mass of solute

Now put all the given values in the above formula, we get

$273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}$

By rearranging the terms, we get the freezing point of solution.

$T_f=260.503K$

Therefore, the freezing point of the solution is, 260.503 K

6 0

3 years ago

A sample of octane burns releasing 2290 J of heat to the surroundings, and the gases produced expands against a piston to do 560

dexar [7]

Answer: The internal energy change for the reaction is -2850 J

Explanation:

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

Sign convention of work:

Work done for expansion process is taken as negative and work done for compression is taken as positive.

According to the First law of thermodynamics,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat absorbed or released = -2290 J

w = work done = -560 J

Putting values in above equation, we get:

$\Delta U=(-2290)+(-560)\\\\\Delta U=-2850J$

Hence, the internal energy change for the reaction is -2850 J

4 0

3 years ago

A 6.26 g sample of a solid containing ni is dissolved in 20.0 ml water. a 5.00 ml aliquot of this solution is diluted to 100.0 m

saveliy_v [14]

Concentration of Ni in 20mL = 5.28ppm x dilution factor = 5.28 x 100/5 = 105.6 ppm = 105.6 mg/L

molar mass of Ni = 58.6934 g
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5 0

3 years ago

Potassium has nineteen protons. how many electrons does a neutral potassium atom have?

Flauer [41]

It has 19 electrons. I hope this helps.

8 0

3 years ago

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