Answer:
The correct answer is vertebrate enzyme hydrolyze alpha-1,4 glycosidic linkage but not glucose in the beta configuration.
Explanation:
The amylase that is present inside human body is called salivary alpha amylase,an enzyme that digest the alpha-1,4-glycosidic linkages of starch but does not act on those glycosidic linkages which are present in beta configuration.
Cellulose contain beta-1,4-glycosidic linkages.That"s why it is not digested by the alpha amylase enzyme present inside the human body basically present in the saliva.
Answer:
2.067 L ≅ 2.07 L.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),</em>
It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.
- At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:
It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
<u><em>using cross multiplication:</em></u>
1.0 mol of O₂ represents → 22.4 L.
??? mol of O₂ represents → 3.1 L.
∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.
- To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:
<u><em>Using cross multiplication:</em></u>
3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.
0.1384 mol of O₂ produce → ??? mol of SO₂.
∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.
- Again, using cross multiplication:
1.0 mol of SO₂ represents → 22.4 L, at STP.
0.09227 mol of SO₂ represents → ??? L.
∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.
Answer: hydrogen is the limiting reactant.
Explanation:
We have the equation 
.
This means that for every mole of nitrogen consumed, 3 moles of hydrogen are consumed.
- Considering the nitrogen, the reaction can occur 0.50 times.
- Considering the hydrogen, the reaction can occur 1.8/3 = 0.6 times.
Therefore, <u>hydrogen</u> is the limiting reactant.
Formula 1!!!!!!!!!!!!!!!!!!!!!!!!!!
