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Readme [11.4K]
3 years ago
13

For a specific volume of 0.2 m3/kg, find the quality of steam if the absolute pressure is (a) 40 kPa and (b) 630 kPa. What is th

e temperature of each case?
Physics
1 answer:
ICE Princess25 [194]3 years ago
4 0

Answer:

x=0.0498

x'=0.659

Explanation:

Specific Volume V=0.2m_3/kg

Absolute Pressure (a) P_a= 40kpa

Giving

T_a=75.87

v_f=1.265*10^{-3}m^3/kg

v_g=3.993m^3/kg

                               (b) P_a= 630kpa

Giving

T_b=160.13C

v_f'=1.10282*10^{-3} m^3/kg

v_g'=0.30286 m^3/kg

(a)

Generally the equation for quality of Steam X  is mathematically given by

x=\frac{v-v_f}{v_g-v_f}

x=\frac{0.2-1.0265*10^{-3}}{3.993-1.0265*10^{-3}}

x=0.0498

(b)

Generally the equation for quality of Steam X  is mathematically given by

x'=\frac{v-v_f'}{v_g'-v_f'}

x'=\frac{0.2-1.10*10^{-3}}{3.30-1.1*10^{-3}}

x'=0.659

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Three moles of an ideal gas with a molar heat capacity at constant volume of 4.9 cal/(mol∙K) and a molar heat capacity at consta
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Answer:

The heat flows into the gas during this two-step process is 120 cal.

Explanation:

Given that,

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Initial temperature = 300 K

Final temperature = 320 K

We need to calculate the heat flow in to gas at constant pressure

Using formula of heat

\Delta H_{1}=nC_{p}\times\Delta T

Put the value into the formula

\Delta H_{1}=3\times6.9\times(320-300)

\Delta H_{1}=414\ cal

We need to calculate the heat flow in to gas at constant volume

Using formula of heat

\Delta H_{1}=nC_{v}\times\Delta T

Put the value into the formula

\Delta H_{1}=3\times4.9\times(300-320)

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horsena [70]

Answer:

V = 493421.05 [gal]

Explanation:

This is a problem that consists of handling units, we can calculate by first-hand the volume, then convert units from cubic meters to gallons.

V = 50 * 25 * 1.5

V = 1875 [m^3]

Now we need to convert units, using the proper conversion factor.

1875[m^3]*\frac{1000lt}{1m^3} *\frac{1gal}{3.8lt} \\493421.05[gal]

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