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3 years ago

In a (an) _______________, electrons are shared.

Physics

1 answer:

Molodets [167]3 years ago

8 0

in a (an) covalent bond, electrons are shared.

In a (an) ionic bond, electrons are lost or gained.

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At room temperature, an oxygen molecule, with mass of 5.31x10^-26kg , typically has a kinetic energy of about 6.21x10^-21J. How

den301095 [7]

Answer:

V=483.63 m/s

Explanation:

Given that

mass ,m= 5.31 x 10⁻²⁶ kg

Kinetic energy KE= 6.21 x 10⁻²¹ J

As we know that the kinetic energy of the mass m with moving velocity V given as

$KE=\dfrac{1}{2}mV^2$

Now by putting the values

$6.21\times 10^{-21}=\dfrac{1}{2}\times 5.31\times 10^{-26}\times V^2$

$V^2=\dfrac{2\times 6.21\times 10^{-21}}{5.31\times 10^{-26}}$

$V^2=233898.30$

$V=\sqrt{233898.30}\ m/s$

V=483.63 m/s

Therefore the velocity of the molecule at the room temperature will be 483.63 m/s.

6 0

4 years ago

In electroplating, the object to be plated is which part of an electrolytic cell? cathode or anode

Bingel [31]

Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

Please mark me as brainliest.

7 0

3 years ago

Read 2 more answers

Starting from rest a model rocket accelerates upwards at 24 m/s2. How fast will it be moving after it has traveled 192 meters?

Gekata [30.6K]

Answer: 96 m/s

Explanation:

Given information

Acceleration of rocket = 24 m/s2

Distance travelled by rocket = 192 meters.

To be calculated

Velocity of rocket at 192 meters = ?

Using 2nd equation of motion, the difference of square of final and initial velocity is equal to the 2 times the product of acceleration and distance.

v2 – u2 = 2as

v2 – 0 = 2 * 24 * 192 (intial velocity is 0, so u = 0)

v2 = 9216

v = $\sqrt9216$

v = 96 m/s

5 0

4 years ago

Kingda Ka has a maximum speed of 57.2 m/s. Determine the height of the hill on this roller coaster. Explain to get full credit,

kodGreya [7K]

This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.

The height of the hill is "166.76 m".

<h3>LAW OF CONSERVATION OF ENERGY:</h3>

According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:

$Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\
\frac{1}{2}mv_{max}^2=mgh\\\\
h=\frac{v_{max}^2}{2g}$