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sammy [17]
3 years ago
15

Are the properties of rubidium more like those of cesium or those of strontium ? Explain your ans

Physics
1 answer:
Citrus2011 [14]3 years ago
7 0

Answer:

Cesium.

Explanation:

For non-transition elements such as rubidium, cesium, and strontium, the most chemically similar element to any other element is always one in the same column of the periodic table but in an adjacent row. Since strontium is not in the same column as rubidium but cesium is in the same column and an adjacent row, the answer follows. (This rule is sometimes true also for transition elements, but not always: For example, for elements in columns 8, 9, and 10, the most nearly chemically similar element is one in the same row and an adjacent column within this group, rather than one in the same column but an adjacent row.)

Hope This Helps!

God Bless

~DuffyDuck~

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An electron moving with a velocity = 5.0 × 10 7 m/s enters a region of space where perpendicular electric and a magnetic fields
inna [77]

Answer:

The magnetic field is 2 \times 10^{-4} T

Explanation:

Given:

Velocity of electron v = 5 \times 10^{7} \frac{m}{s}

Electric field E = 10^{4} \frac{V}{m}

The force on electron in magnetic field is given by,

 F = qvB \sin \theta                      ......(1)

The force on electron in electric field is given by,

 F = qE                               ......(2)

Compare both equation,

   qE = qvB \sin \theta

Here \sin \theta = 1

  E = vB

  B= \frac{E}{v}

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Therefore, the magnetic field is 2 \times 10^{-4} T

5 0
3 years ago
Adding heat to a liquid causes which of the following physical changes?
kow [346]
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3 0
3 years ago
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
Virty [35]

Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

8 0
2 years ago
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