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Vladimir [108]
2 years ago
12

If the work function for a certain metal is 1.8eV, what is the stopping potential for electrons ejected from the metal when ligh

t of wavelength 400nm shines on the metal? And what is the maximum speed of the ejected electrons? ...?
Physics
1 answer:
taurus [48]2 years ago
8 0
First of all the equation you need is this one
<span>E=<span>Ek</span>+ϕ</span> <span><span>Ek</span>=e<span>V0
</span></span>Please remember that the energy of a photon of wavelength lambda is given by <span>E=<span><span>hc</span>λ

</span></span>you can then calculate the maximum kinetic energy since you know the work function of the metal (1.8eV), and the wavelength of the photons (400 nm) (remembering to convert to SI units of joules for the work function). You can then find the maximum velocity of the electrons easy enough.You can obtain the stopping potential usign the next formula
Ek=eV0
<span>Because it is a stopping voltage, V_{0}  and remember it will have the units of volts.
</span>I think with that I can help you a lot. 
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2 years ago
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A string under a tension of 50.4 N is used to whirl a rock in a horizontal circle of radius 2.51 m at a speed of 21.1 m/s. The s
Leokris [45]

Answer:

619.8 N

Explanation:

The tension in the string provides the centripetal force that keeps the rock in circular motion, so we can write:

T=m\frac{v^2}{r}

where

T is the tension

m is the mass of the rock

v is the speed

r is the radius of the circular path

At the beginning,

T = 50.4 N

v = 21.1 m/s

r = 2.51 m

So we can use the equation to find the mass of the rock:

m=\frac{Tr}{v^2}=\frac{(50.4)(2.51)}{21.1^2}=0.284 kg

Later, the radius of the string is decreased to

r' = 1.22 m

While the speed is increased to

v' = 51.6 m/s

Substituting these new data into the equation, we find the tension at which the string breaks:

T'=m\frac{v'^2}{r'}=(0.284)\frac{(51.6)^2}{1.22}=619.8 N

5 0
3 years ago
A 120.0 kg crate is placed on a 15.00°
Citrus2011 [14]

F = 2820.1 N

Explanation:

Let the (+)x-axis be up along the slope. The component of the weight of the crate along the slope is -mgsin15° (pointing down the slope). The force that keeps the crate from sliding is F. Therefore, we can write Newton's 2nd law along the x-axis as

Fnet = ma = 0 (a = 0 no sliding)

= F - mgsin15°

= 0

or

F = mgsin15°

= (120 kg)(9.8 m/s^2)sin15°

= 2820.1 N

7 0
2 years ago
Study the following circuits. Differentiate between the two. ​
MAVERICK [17]

Here (X) is a parallel combination of resistors whereas it is series combination of resistors in (Y).

Hope this is the answer you're looking for. If it is correct then mark my answer as the brainliest!  :)

8 0
2 years ago
How do you delete a brainly question
Likurg_2 [28]

Answer:

you can't

Explanation:

you can only comment on your question and add more details or can ask a moderator or administrator to remove your question with a reason

3 0
2 years ago
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