Answer:
A. 4.08 s
B. 141 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 40 m/s
Angle of projection (θ) = 30°
A. Determination of the time of flight.
Initial velocity (u) = 40 m/s
Angle of projection (θ) = 30°
Acceleration due to gravity (g) = 9.8 m/s²
Time of flight (T) =?
Thus, we can obtain the time of flight (i.e how long the ball stayed in the air) as follow:
T = 2u Sineθ/g
T = 2 × 40 × Sine 30 / 9.8
T = 80 × 0.5 / 9.8
T = 40 /9.8
T = 4.08 s
B. Determination of the range
Initial velocity (u) = 40 m/s
Angle of projection (θ) = 30°
Acceleration due to gravity (g) = 9.8 m/s²
Range (R) =?
The range can be obtained as follow:
R = u² Sine 2θ /g
R = 40² × Sine(2×30) / 9.8
R = 1600 × Sine 60 / 9.8
R = 1600 × 0.866 / 9.8
R = 1385.6 / 9.8
R = 141.3 ≈ 141 m