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Lapatulllka [165]

3 years ago

9

If you took a wire, connected one end to a rechargeable battery, and connected the other end to the leaf of a plant, would you b

e able to extract electricity from the plant ?

1 answer:

astraxan [27]3 years ago

7 0

Answer:

No bcz it is insulator it will not conduct electric

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Lie on a bed?<br> What type of force are you exerting when you

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Static force is being exerted

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3 years ago

Define cation and anion. In which case are electrons gained? Lost?

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Explanation:

A cation is a positively charged ion.

An anion is a negatively charged ion.

In a cation, electrons are usually lost
In an anion, electrons are usually gained.

In an atom, the balance between the number of protons and electrons determine whether they become an anion or cation.

Protons are positively charged particles.

Electrons are negatively charged

When an atom gains electrons, the number of electrons becomes more than that of protons. This leaves a net negative charge on the atom and it makes an anion.

When an atom loses electrons, the number of protons becomes more than that of electrons. This leaves a net positive charge on the atom and makes a cation.

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Which of the following is NOT useful in

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2 years ago

What is the chemical formula for ammonium carbonate?

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To correct chemical formula for ammonium carbonate is the first option

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3 years ago

A block of aluminum weighing 140 g is cooled from 98.4°C to 62.2°C with the release of 1080 joules of heat. From this data, calc

GrogVix [38]

<u>Answer:</u>

Specific heat of a substance is the value that describe how the added heat energy of substance has the impact on its temperature.

Unit is <em> $(\frac {J}{Kg.K})$ </em>

<em>C = Q/m. ∆T</em>

<em>C – Specific heat $(\frac {J}{Kg.K})$ </em>

<em>Q- heat energy (J)</em>

<em>M – Mass (Kg)</em>

<em>∆T- change in temperature (K) </em>

<u>Explanation:</u>

<em>Given data:</em>

<em>M= 140 g = 0.14 Kg</em>

<em>Q – 1080 Joules.</em>

<em>∆T – 98.4 – 62.2 = 36.2</em>

Substituting the given data in Equation

<em>Specific heat of Aluminium = $\frac {1080}{(0.14 \times 36.2)} = 213.10 (\frac {J}{Kg.K})$ </em>

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3 years ago

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