Answer:
hello your question has a missing part below is the missing part
Consider the string length equal to ![\pi](https://tex.z-dn.net/?f=%5Cpi)
answer : 2cos(2t) sin(2x) - 10cos(10t)sin(10x)
Explanation:
Given string length =
distorted function f(x) = 2sin(2x) - 10sin(10x)
Determine the wave formed in the string
attached below is a detailed solution of the problem
Answer:
The rate of entropy change of the air is -0.10067kW/K
Explanation:
We'll assume the following
1. It is a steady-flow process;
2. The changes in the kinetic energy and the potential energy are negligible;
3. Lastly, the air is an ideal gas
Energy balance will be required to calculate heat loss;
mh1 + W = mh2 + Q where W = Q.
Also note that the rate of entropy change of the air is calculated by calculating the rate of heat transfer and temperature of the air, as follows;
Rate of Entropy Change = -Q/T
Where Q = 30Kw
T = Temperature of air = 25°C = 298K
Rate = -30/298
Rate = -0.100671140939597 KW/K
Rate = -0.10067kW/K
Hence, the rate of entropy change of the air is -0.10067kW/K
Answer:
b
Explanation:
the NEC has expanded the requirements for ground-fault circuit interrupters (GFCI) to protect anyone who plugs into an electrical system. Initially, it was only required for temporary wiring at construction sites and in dwelling unit bathrooms, but in recent years the Code requirements for GFCI protection have expanded to include many other areas, including commercial occupancies, fountains and swimming pools, and temporary installations, to name a few. (For a complete list of 2002 NEC references, see the sidebar below)
Answer:21.3%
Explanation:
Given
80 % reduction in tool life
According to Taylor's tool life
=c
where V is cutting velocity
T=tool life of tool
80 % tool life reduction i.e. New tool Life is 0.2T
Thus
![VT^{0.12}=V'\left ( 0.2T\right )^{0.12}](https://tex.z-dn.net/?f=VT%5E%7B0.12%7D%3DV%27%5Cleft%20%28%200.2T%5Cright%20%29%5E%7B0.12%7D)
![V'=\frac{V}{0.2^{0.12}}](https://tex.z-dn.net/?f=V%27%3D%5Cfrac%7BV%7D%7B0.2%5E%7B0.12%7D%7D)
=1.213V
Thus a change of 21.3 %(increment) is required to reduce tool life by 80%
Answer:
<h2>500 kG con 0 .3 </h2>
Explanation:
<h2>700 gramos</h2>