The drawbar or other connections must be strong enough to pull all the weight of the vehicle being towed. The drawbar or other connection may not exceed 15 feet from one vehicle to the other.
Answer:
For This Answer Please See the Attached File.
Explanation:
Answer:
a) 2.18 m/s^2
b) 9.83 m/s
Explanation:
The flywheel has a moment of inertia
J = m * k^2
Where
J: moment of inertia
k: radius of gyration
In this case:
J = 144 * 0.45^2 = 29.2 kg*m^2
The block is attached through a wire that is wrapped around the wheel. The weight of the block causes a torque.
T = p * r
r is the radius of the wheel.
T = m1 * g * r
T = 18 * 9.81 * 0.6 = 106 N*m
The torque will cause an acceleration on the flywheel:
T = J * γ
γ = T/J
γ = 106/29.2 = 3.63 rad/s^2
SInce the block is attached to the wheel the acceleration of the block is the same as the tangential acceleration at the eddge of the wheel:
at = γ * r
at = 3.63 * 0.6 = 2.81 m/s^2
Now that we know the acceleration of the block we can forget about the flywheel.
The equation for uniformly accelerated movement is:
X(t) = X0 + V0*t + 1/2*a*t^2
We can set a frame of reference that has X0 = 0, V0 = 0 and the X axis points in the direction the block will move. Then:
X(t) = 1/2*a*t^2
Rearranging
t^2 = 2*X(t)/a


It will reach the 1.8 m in 3.6 s.
Now we use the equation for speed under constant acceleration:
V(t) = V0 + a*t
V(3.6) = 2.81 * 3.6 = 9.83 m/s
Answer:
Highest temperature rise allowable = ΔT = 21.22°C
Highest allowable temperature = ΔT + 20 = 41.22°C
Explanation:
From literature, the coefficient of volume expansion of water between 20°C and 50°C = β = (0.377 × 10⁻³) K⁻¹
Volume expansivity is given by
ΔV = V β ΔT
ΔV = Change in volume
V = initial volume
β = Coefficient of volume expansion = (0.377 × 10⁻³) K⁻¹ = 0.000377 K⁻¹
ΔT = Change in temperature = ?
It is given in the question that maximum volume increase the tank can withstand is
(ΔV/V) × 100% = 0.8%
(ΔV/V) = 0.008
V β ΔT = ΔV
β ΔT = (ΔV/V)
β ΔT = 0.008
ΔT = (0.008/β)
ΔT = (0.008/0.000377)
ΔT = 21.22°C
Highest temperature rise allowable = ΔT = 21.22°C
Highest allowable temperature = ΔT + 20 = 41.22°C
Hope this Helps
Answer:
The best way to ensure that OSHA will conduct a site inspection is by the submission a signed (by a current employee or employee representative) Formal Written complaints following OSHA guidelines (which can be found in the Council of Safety and Health (COSH) website) which will enable the commencement of process for an on site inspection
As such it is advisable to go through the following procedure before, filing a complaint
1) Talk to your workers union about the hazard
2) If you do not belong to a union, talk to your co-workers
3) Inform your employer who has responsibility for on the job safety
4) Speak or have a meeting with OSHA so as to receive guidance before filing a complaint
Explanation: