Answer:
Follows are the solution to this question:
Explanation:
Calculating the area under the curve:
A = as

Calculating the kinematics equation:


Calculating the value of acceleration:




Answer:

Explanation:
By Gauss Law for electric field:

Where
is the charge density Q/A. Since we have 2 parallel plates with different charge, the electric field at point P in the gap would be the sum of 2 field



Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness
= 92 Mpa√m
yield strength σ
= 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length
= 1/π(
/ Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{
= ( 10.06 mm ) > 3 mm
The critical flow is subject to detection
Answer:
37 psi
Explanation:
For ideal gases this equation applies:
p1*V1/T1 = p2*V2/T2
Since we are assuming volume remains constant:
V2 = V1
p1/T1 = p2/T2
p2 = p1*T2/T1
The temperatures must be in absolute scale.
T1 = 15 + 273 = 288 K
T2 = 60 + 273 = 333 K
Then:
p2 = 32 * 333 / 288 = 37 psi