Question

Which tile should be used to solve the following problem? I will give brainliest PLEASE HELP

Answer 1

Answer: B. $\frac{\text {2 mol} H_2O}{\text {2 mol HCl}}$

Explanation:

The balanced chemical equation is:

$Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)$

is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

2 moles of produce = 2 moles of

Thus 3.25 moles of $HCl$ will produce=$\frac{2}{2}\times 3.25=3.25moles$  of $H_2O$

Thus the tile used is $\frac{\text {2 mol } H_2O}{\text {2 mol HCl}}$