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Tom [10]
3 years ago
13

Two laws are described below:

Physics
2 answers:
Ber [7]3 years ago
8 0

Answer:Law A is a societal law and Law B is a scientific law.

Explanation:

sergejj [24]3 years ago
7 0

Answer:

Answer: D

Law A is a social law and Law B is a scientific law.

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12
makkiz [27]

Answer:

i done know sorry for not answering ur question

3 0
3 years ago
What are two ways in which friction can be useful?
pishuonlain [190]
If something is going down a hill it can help slow it down

it can stop you from flying off a rollercoaster
6 0
3 years ago
Read 2 more answers
Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou
Gennadij [26K]

Answer:

a. The station is rotating at 1.496 \frac{rev}{min}

b. the rotation needed is 2.8502 \frac{rev}{min}

Explanation:

We know that the centripetal acceleration is

a_{c}= \omega ^2 r

where \omega is the rotational speed and r is the radius. As the centripetal acceleration is feel like an centrifugal acceleration in the rotating frame of reference (be careful, as the rotating frame of reference is <u>NOT INERTIAL,</u> the centrifugal force is a fictitious force, the real force is the centripetal).

<h3>a. </h3>

The rotational speed  is :

2.7 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{2.7 \frac{m}{s^2}} {110 \ m}

\omega  = \sqrt{ 0.02454 \frac{rad^2}{s^2} }

\omega  = 0.1567 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.1567 \frac{rad}{s}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 1.496 \frac{rev}{min}

<h3>b. </h3>

The rotational speed needed is :

9.8 \frac{m}{s^2} = \omega ^2 * 110  \ m

\omega ^2 = \frac{9.8 \frac{m}{s^2}} {110 \ m}

\omega  = \sqrt{ 0.08909 \frac{rad^2}{s^2} }

\omega  = 0.2985 \frac{rad}{s}

Knowing that there are 2\pi \ rad in a revolution and 60 seconds in a minute.

\omega  = 0.2985 \frac{rev}{min}  \frac{1 \ rev}{2\pi \ rad} \frac{60 \ s}{1 \ min}

\omega  = 2.8502 \frac{rev}{min}

3 0
3 years ago
Read 2 more answers
How much work is done if a force of 20 N moves an object a distance of 6 m?​
Nesterboy [21]

Explanation:

W=F×s

w=20N×6m=120J

W=120J

3 0
3 years ago
In concave mirror, the size of image depends upon
irina1246 [14]

Answer:

The distance of the object placed on the principal axis from the concave mirror.

Explanation:

In a concave mirror, the nature of the image formed formed by the object placed in front of the mirror depends on the position of the object placed in from of the mirror. It all depends on the distance between the mirror and the object placed on the principal axis.

The closer the object is to the lens, the more larger or magnified the image formed will be. For example an object placed between the focal point and the pole of a concave produces a much larger image than an object placed beyond the centre of curvature of such mirror.

8 0
3 years ago
Read 2 more answers
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