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3 years ago

11

Round or fraction form round all the WAY!

1 answer:

maw [93]3 years ago

3 0

Answer:

The answer to the question provided is

$- \frac{3}{2}$

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How to convert the angle measure to decimal degree form on calculator?

ArbitrLikvidat [17]

If an angle is given in minutes and seconds of an arc as well as degrees, remember that a minute is a sixtieth of a degree and a second is a sixtieth of a minute. For example, 20º35’26” is the same as 20+(35+26/60)/60. Your calculator will give you a decimal result of this calculation.

8 0

3 years ago

Sophia has an ear infection. The doctor prescribes a course of antibiotics. Sophia is told to take 500 mg doses of the antibioti

olganol [36]

Answer:

Dosage= 500 mg

Frequency= twice a day (every 12 hours)

Duration= 10 days

Number of dosage= 10*2= 20

residual drug amount after each dosage= 4.5%

We can build an equation to calculate residual drug amount:

d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage

After first dose residual drug amount is: d= 500*0.045= 22.5 mg

After second dose: d= 22.5*2= 45 mg

As per the equation, the higher the t, the greater the residual drug amount in the body.

Maximum drug will be in the body:

d= 20*22.5= 450 mg at the end of 10 days

Maximum drug will be in the body right after the last dose, when the amount will be:

500+19*22.5= 927.5 mg

6 0

4 years ago

The weights of 83 randomly selected windshields were found to have a variance of 1.88. Construct the 95% confidence interval for

Morgarella [4.7K]

Answer:

95% confidence interval for the population variance = (1.42 , 2.62).

Step-by-step explanation:

We are given that the weights of 83 randomly selected windshields were found to have a variance of 1.88.

<em>So, firstly the pivotal quantity for 95% confidence interval for the population variance is given by;</em>

P.Q. = $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

where, $s^{2}$ = sample variance = 1.88

$\sigma^{2}$ = population variance

n = sample of windshields = 83

So, 95% confidence interval for population variance, $\sigma^{2}$ is;

P(58.85 < $\chi^{2} __8_2$ < 108.9) = 0.95 {As the table of $\chi^{2}$ at 82 degree of freedom

gives critical values of 58.85 & 108.9}

P(58.85 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 108.9) = 0.95

P( $\frac{ 58.85}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{108.9}{(n-1)s^{2} }$ ) = 0.95

P( $\frac{ (n-1)s^{2}}{108.9 }$ < $\sigma^{2}$ < $\frac{ (n-1)s^{2}}{58.85 }$ ) = 0.95

<em><u>95% confidence interval for</u></em> $\sigma^{2}$ = ( $\frac{ (n-1)s^{2}}{108.9 }$ , $\frac{ (n-1)s^{2}}{58.85 }$ )

= ( $\frac{ (83-1)\times 1.88}{108.9 }$ , $\frac{ (83-1)\times 1.88}{58.85 }$ )

= (1.42 , 2.62)

Therefore, 95% confidence interval for the population variance of the weights of all windshields in this factory is (1.42 , 2.62).

8 0

3 years ago

A running trail is 63 miles long. Leigh plans on

nadezda [96]

Answer:

63/4 or 15 3/4 miles each day

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Part B Which of these statements are true? Choose all that apply. . А More than 20% of girls and more than 20% of boys chose mat

kenny6666 [7]

Is there a sort of graph that I could look at and then I could tell, because I don’t just know this information off the top of my head.

4 0

3 years ago