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gayaneshka [121]
2 years ago
5

How many grams of NH3 can be prepared from 77.3 grams of N2 and 24.2 grams of H2?

Chemistry
1 answer:
blondinia [14]2 years ago
4 0

Answer:

how many grams of NH3 can be prepared from 77.3 grams of N2 and 24.2 grams of H2?

=80.4 g

Explanation:

I think.

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Because of its high heat content, the most valuable type of coal is __________.
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C.
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2 years ago
To determine the concentration of SO4 2– ion in a sample of groundwater, 100.0 mL of the sample is titrated with 0.0250 M Ba(NO3
Brrunno [24]

Answer:

1.87x10⁻³ M SO₄²⁻

Explanation:

The reaction of SO₄²⁻ with Ba²⁺ (From Ba(NO₃)₂) is:

SO₄²⁻(aq) + Ba²⁺(aq) → BaSO₄(s)

<em>Where 1 mole of  SO₄²⁻ reacts per mole of Ba²⁺</em>

<em />

To reach the end point in this titration, we need to add the same moles of Ba²⁺ that the moles that are of SO₄²⁻.

Thus, to find molarity of SO₄²⁻ we need to find first the moles of Ba²⁺ added (That will be the same of SO₄²⁻). And as the volume of the initial sample was 100mL we can find molarity (As ratio of moles of SO₄²⁻ per liter of solution).

<em>Moles Ba²⁺:</em>

7.48mL = 7.48x10⁻³L ₓ (0.0250moles / L) = 1.87x10⁻⁴ moles of Ba²⁺ = Moles of SO₄²⁻

<em>Molarity SO₄²⁻:</em>

As there are 1.87x10⁻⁴ moles of SO₄²⁻ in 100mL = 0.1L, molarity is:

1.87x10⁻⁴ moles of SO₄²⁻ / 0.1L =

<h3> 1.87x10⁻³ M SO₄²⁻</h3>
8 0
3 years ago
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