Answer:
B splits and goes through two components
Explanation:
- A series circuit is a circuit in which the components are all connected along the same branch: as a result, the current flowing through the components is the same, while the sum of the potential differences across each component is equal to the emf of the battery
- A parallel circuit is a circuit consisting of separate branches, so that each branch has a potential difference equal to the emf of the battery. As a result, in such a circuit the current in the circuit splits and goes through the different branches/components.
So, the correct answer is
B splits and goes through two components
Answer:
total surface area is 432
Explanation:
Given data
base = 6
diagonals = 8
altitude = 12
to find out
total surface area
solution
we know total surface area of prism is
total surface area = lateral surface area + 2base area ..............1
so
first we calculate base perimeter i.e = 2 length + 2 width
so perimeter = 2(8) + 2(6) = 25
and area = length * width = 8*6 = 48
so lateral surface area is perimeter * height i.e
lateral surface area = 28* 12
lateral surface area = 336
put this value in equation 1 we get
total surface area = lateral surface area + 2base area
total surface area = 336 + 2(48)
total surface area is 432
Answer:
Acosθ
Explanation:
The x-component of a vector is defined as :
Magnitude * cosine of the angle
Maginitude * cosθ
The magnitude is represented as A
Hence, horizontal, x - component of the vector is :
Acosθ
Furthermore,
The y-component is taken as the sin of the of the angle multiplied by the magnitude
Vertical, y component : Asinθ
Answer:
Explanation:
The voltage of a disconnected charged capacitor increases when the plate area is decreased.
When plate area decreases , capacitance C decreases , but charge Q remains constant .
Q = C V where C is capacitance and V is voltage .
when C decreases , V increases for keeping Q constant .
So the statement is true.
The electric field is dependent on the charge density on the plates.
This statement is true .
The voltage of a connected charged capacitor remains the same when the plate area is decreased .
For a connected capacitor , V or voltage is constant which is equal to voltage of charging battery .
So the statement is true .
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