All categories

3 years ago

What is the relationship between the applied force of a hanging mass on a spring and the spring force of the spring?

Physics

1 answer:

zaharov [31]3 years ago

7 0

Answer:

elastic force and weight are related to the acceleration of the System.

Explanation:

The relationship between these two forces can be found with Newton's second law.

$F_{e}$ - W = m a

K x - m g = m a

We see that elastic force and weight are related to the acceleration of the System.

If a harmonic movement is desired, an extra force that increases the elastic force is applied, but to begin the movement this force is eliminated, in general , if the relationship between this external and elastic force is desired, the only requirement is that it be small for harmonic movement to occur

You might be interested in

According to the Big Bang Theory, the density and temperature of the Universe is ___________ now than in the past.

34kurt

Answer:

According to the Big Bang Theory, the density and temperature of the Universe is lower now than in the past.

Hope this answer correct :)

5 0

3 years ago

When a wave is acted upon by an external damping force, what happens to the energy of the wave

Rasek [7]

The energy of the wave decreases gradually

8 0

3 years ago

Read 2 more answers

the jet plane travels along the vertical parabolic path. when it is at point a it has speed of 200 m/s, which is increasing at t

givi [52]

Explanation:

Here is the complete question i guess. The jet plane travels along the vertical parabolic path defined by y = 0.4x². when it is at point A it has speed of 200 m/s, which is increasing at the rate .8 m/s^2. Determine the magnitude of acceleration of the plane when it is at point A.

→ The tangential component of acceleration is rate of increase in the speed of plane so,

$a_{t} = v = 0.8 m/s^{2}$

→ Now we have to find out the radius of curvature at point A which is 5 Km (from the figure).

dy/dx = d(0.4x²)/dx

= 0.8x

Take the derivative again,

d²y/dx² = d(0.8x)/dx

= 0.8

at x= 5 Km

dy/dx = 0.8(5)

= 4

$p = \frac{[1+ (\frac{dy}{dx})^{2}]^{\frac{3}{2} } }{\frac{d^{2y} }{dx^{2} } }$

now insert the values,

$p = \frac{[1+(4)^{2}]^{\frac{3}{2} } }{0.8} = 87.62 km$

→ Now the normal component of acceleration is given by

$a_{n} = \frac{v^{2} }{p}$

= (200)²/(87.6×10³)

aₙ = 0.457 m/s²

→ Now the total acceleration is,

$a = [(a_{t})^{2} +(a_{n} )^{2} ]^{0.5}$

$a = [(0.8)^{2} + (0.457)^{2}]^{0.5}$

a = 0.921 m/s²

4 0

3 years ago

What will make two bar magnets repel each other?

Kitty [74]

The arrows always start at the magnet's north pole and point towards its south pole. When two like-poles point together, the arrows from the two magnets point in OPPOSITE directions and the field lines cannot join up. So the magnets will push apart

6 0

2 years ago

A patricle is accelerated uniformly from rest, so that after 10 seconds it has a speed of 15m/s find its acceleration and the di

grin007 [14]

Answer:

Its acceleration is 1.5 $\frac{m}{s^{2} }$ and the distance it has covered is 150 m.

Explanation:

Acceleration is a quantity that indicates the variation in speed of a moving body as time passes. That is, acceleration relates changes in velocity with the time in which they occur.

The average acceleration is defined as the relationship between the variation or change in the speed of a mobile and the time used in said change:

$acceleration=\frac{change in speed}{time}$

In this case:

change in speed= final speed - initial speed= 15 m/s - 0 m/s= 15 m/s
time= 10 s

Replacing:

$acceleration=\frac{15 \frac{m}{s} }{10 s}$

and solving you get:

acceleration= 1.5 $\frac{m}{s^{2} }$

Speed is a quantity that expresses the relationship between the space traveled by an object and the time used for it. This is:

$speed=\frac{distance}{time}$

So the distance can be calculated as:

distance= speed* time

In this case:

speed= 15 m/s
time= 10 s

Replacing:

distance= 15 m/s* 10 s

and solving you get:

distance= 150 m

Its acceleration is 1.5 $\frac{m}{s^{2} }$ and the distance it has covered is 150 m.

8 0

3 years ago