A. Two point charges totaling 7.50 µC exert a repulsive force of 0.100 N on one another when separated by 0.911 m. What is the c
1 answer:
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I attached the full question.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
Please note that elecric permittivity of air is very close to elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
Please note that elecric permittivity of air is very close to elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.
Answer:
Upward force on the boy will be 1024 N
Explanation:
We have given mass of the boy m = 80 kg
Acceleration due to gravity
It is given that elevator is ascending with acceleration of
So net acceleration on the boy = 9.8+3 = 12.8 ( As the car elevator is moving ascending )
So upward force on the boy will be equal to F = m(g+a)
So
So upward force on the boy will be 1024 N