A. Two point charges totaling 7.50 µC exert a repulsive force of 0.100 N on one another when separated by 0.911 m. What is the c
1 answer:
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Answer:
Explanation:
Change in velocity considering the x component will be
Final velocity-Initial velocity
Change in velocity considering the y component will be
Final velocity-Initial velocity
Resultant change in velocity
Acceleration= change in velocity per unit time hence
Answer:
T = 451.26 N
Explanation:
It is given that,
The mass of block, m = 46 kg
Mass of the chain, m' = 19 kg
Length of the chain, l = 1.9 m
Let T is the the tension in the chain at the point where the chain is supporting the block. It is clearly equal to the product of mass and acceleration.
T = 451.26 N
So, the tension in the chain at the point where the chain is supporting the block is 451.26 N. Hence, this is the required solution.