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eduard
3 years ago
6

A. Two point charges totaling 7.50 µC exert a repulsive force of 0.100 N on one another when separated by 0.911 m. What is the c

harge (in µC) on each?
smallest charge:

largest charge:

b. What is the charge (in µC) on each if the force is attractive?
smallest
largest
Physics
1 answer:
andriy [413]3 years ago
7 0

coulomb's law

f repulsive = q1q2/4 pi epsilon nought r squared

0.1= q1q2/4 pi epsilon nought 0.911 squared

q1+q2= 7.50 µC

0.1= q1(7.5µC-q1)/4 pi epsilon nought 0.911 squared

solve for q1

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Answer:

F = MA

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3 years ago
The special theory of relativity deals with space and time under what special condition?
sergij07 [2.7K]
<h2>Answer: Invariance of the speed of light in vacuum  </h2>

Special relativity was proposed on 1905 by Einstein, who developed his theory based on the following two postulates:  

<em>1. The laws of physics are the same in all inertial systems. There is no preferential system.  </em>

<em>2. The speed of light in vacuum has the same value for all inertial systems.  </em>

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In addition, it deals with the <u>dilation of time</u> stating that <u>time passes at different rates in regions of different gravitational potential</u>. That is, the greater the local distortion of space-time due to gravity, the slower the time passes.  

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7 0
2 years ago
The energy that's given to the body by food is A. measured in units called calories. B. best obtained by eating high protein. C.
mel-nik [20]

Answer:

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4 0
2 years ago
An object is moving at 4.66 m/s when it accelerates at 5.66 m/s2 for a period of 2.35 s. The distance it moves in this time is _
valentinak56 [21]

Answer:

S = 26.58 meters

Explanation:

Given the following data;

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Time = 2.35 seconds

To find the distance travelled by the object, we would use the second equation of motion;

S = ut + ½at²

Where;

S represents the displacement or height measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

S = 4.66*2.35 + ½*5.66*2.35²

S = 10.951 + (2.83 * 5.5225)

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6 0
2 years ago
Four equal masses M are spaced at equal intervals (each of length d) along a horizontal, straight rod whose mass can be ignored.
Mars2501 [29]

Answer:

a) 14Md^{2}

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I = M(0d)^{2}+Md^{2} +M(2d)^{2}+M(3d)^{2}

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b) Your question is incomplete but I'll write how to find the minimum force required  to give a system given angular acceleration.

Minimum force is found when applied from the furthest point to the axis of rotation in the system.

, by τ = Fr, whereτ = torque , F = Force ,  = perpendicular distance from axis of rotation.

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By combining the two equations you get minimum force as,

F = Iα/r

F' = 14Md^{2}α/3d

  = 14Mαd/3

7 0
3 years ago
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