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kap26 [50]
3 years ago
7

As a projectile thrown upward moves in its parabolic path, at what point along its path are the velocity and acceleration vector

s for the projectile perpendicular to each other
Physics
1 answer:
Ivahew [28]3 years ago
5 0

Answer: Maximum height

Explanation:

Suppose a projectile is thrown at an angle of \theta with velocity u

As the projectile moves upward, its vertical component of velocity decreases due to gravity. While the horizontal component remains the same as there is no acceleration in the horizontal direction.  

At maximum height vertical component of velocity is zero. At this instant horizontal component of velocity is perpendicular to the acceleration due to gravity. This can be explained with the diagram.

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Consult Interactive Solution 10.37 to explore a model for solving this problem. A spring is compressed by 0.0647 m and is used t
padilas [110]

Answer:

\omega=32.14\ rad/s

Explanation:

Given that,

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To find,

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Solution,

We know that the elation between the amplitude and the angular frequency in SHM is given by :

v=\omega\times A

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\omega=\dfrac{2.08\ m/s}{0.0647\ m}

\omega=32.14\ rad/s

So, the angular frequency of the spring is 32.14 rad/s.

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3 years ago
A bobsled has a momentum of 3000 kg•m/s to the east. After the rider gives it a push, its momentum increases to 5500 kg•m/s to t
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3 years ago
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