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kap26 [50]
3 years ago
7

As a projectile thrown upward moves in its parabolic path, at what point along its path are the velocity and acceleration vector

s for the projectile perpendicular to each other
Physics
1 answer:
Ivahew [28]3 years ago
5 0

Answer: Maximum height

Explanation:

Suppose a projectile is thrown at an angle of \theta with velocity u

As the projectile moves upward, its vertical component of velocity decreases due to gravity. While the horizontal component remains the same as there is no acceleration in the horizontal direction.  

At maximum height vertical component of velocity is zero. At this instant horizontal component of velocity is perpendicular to the acceleration due to gravity. This can be explained with the diagram.

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Answer:

A. 1,950 J/kgºC

Explanation:

Assuming that all materials involved, finally arrive to a final state of thermal equilibrium, and neglecting any heat exchange through the walls of the calorimeter, the heat gained by the system "water+calorimeter" must be equal to the one lost by the copper and the unknown metal.

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Qg= 0.9 J/gºC*100g*10ºC + 4.186 J/gºC*250g*10ºC  = 11,365 J(1)

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