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charle [14.2K]
2 years ago
11

the diagram below shows the situation described in the problem. the focal length of the lens is labeled f; the scale on the opti

cal axis is in centimeters. draw the three special rays, ray 1, ray 2, and ray 3, as described in the tactics box above, and label each ray accordingly. do not draw the refracted rays.
Physics
1 answer:
Artist 52 [7]2 years ago
8 0

Answer:

I have no clue

Explanation:

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A fisherman is fishing from a bridge and is using a "50.0-N test line." In other words, the line will sustain a maximum force of
umka21 [38]

Answer:(a) 50 N

(b)38.34 N

Explanation:

Given

Maximum tension(T) in line 50 N

(a)If line is moving up with constant velocity i.e. there is no acceleration

This will happen when Tension is equal to weight of Fish

T-mg=0

T=mg

Maximum weight in this case will be 50 N

(b)acceleration of magnitude 2.98 m/s^2

T-mg=ma

50=m\left ( g+a\right )

50=m\left ( 12.78\right )

m=3.91

Therefore weight is 3.91\times 9.8=38.34 N

7 0
3 years ago
A blue textbook will _____<br> green light. A) emit B) reflect C) absorb D) transmit
Tanzania [10]
The answer is C. An object that appears a certain color reflects the light frequency that corresponds to that color, and it absorbs all the other frequencies in the visible light spectrum. An orange absorbs all of the frequencies but orange. A BLUE TEXTBOOK ABSORBS all of the frequencies INCLUDING GREEN except for BLUE.
3 0
3 years ago
Read 2 more answers
Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 2.8 s
Ostrovityanka [42]

Answer:

<em>2.15 mV</em>

<em></em>

Explanation:

The complete question is

You have a coil of wire with 17 turns each of 1.5 cm radius. You place the plane of the coil perpendicular to a 0.50-TB?  field produced by the poles of an electromagnet.

Find the magnitude of the average induced emf in the coil when the magnet is turned off and the field decreases to 0 T in 1.9 s .

Radius of the coil = 1.5 cm = 0.015 m

number of turns = 17

Initial magnetic field B_{1} = 0.50 T

Final magnetic field B_{2} = 0 T

time taken dt = 1.9 s

Area pf the coil = πr^{2} = 3.142 x 0.015^{2} = 7.1 x 10^-4 m^2

magnetic flux = BA

initial flux = B_{1}A = 0.5 x 7.1 x 10^-4 = 3.55 x 10^-4 Wb

Final flux = B_{2}A = 0 x 7.1 x 10^-4 = 0 Wb

change in flux dФ = 3.55 x 10^-4  -  0 = 3.55 x 10^-4 Wb

Induced EMF E = NdФ/dt = (17 x 3.55 x 10^-4)/2.8 = 2.15 x 10^-3 V

==> <em>2.15 mV</em>

7 0
4 years ago
What is lever and explain its working principle​
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Ans: Principle of the lever HTML5

The lever is a simple machine that changes the magnitude and direction of the force applied to move an object. It minimizes the effort required to lift the object. A lever is a rigid bar which moves around a supporting point (pivot or fulcrum). The object to be lifted is placed on the bar.
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How many newtons of force are represented by the following amount: 3 kg·m/sec^2?
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1N=1kg•m/s^2 so the answer is 3N
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