Answer:
potential energy is the energy of an object that is not moving
Explanation:
example a skateboarder stands at the top of the ramp he has no kinetic energy but alot of potential energy when he goes down the ramp he loses the potential energy he has and it transforms into kinetic energy
brinliest plz
Answer:
(B). Liquid sodium or water
Explanation:
I don't know how to explain this But hope it right!
If I'm wrong I'm sorry
If I'm right Thank you and (brainliest plz)
Answer:
60000N
Explanation:
acceleration is change in velocity
a =(v-u)/t where a is acceleration u is initial velocity and v is final velocity
a = (0-60)/5 = -60/5= - 12m/s^2
here minus sign shows that body is decelerating and force is force of friction Now f = ma here f is force of friction m is mass and a is acceleration
f= 5000×- 12= -60000N
MINUS SIGN HERE SHOWS FORCE OF FRICTION
Hence force of friction is 60000N
by cosine law we know that
now using above equation
by solving above quadratic equation we have
so it is at distance 124.9 m from deer a
Answer:
F t = m Δv impulse delivered = change in momentum
Δv = 100 * .1 / .5 = 20 m/s original speed of puck
KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J initial KE of puck
E = μ m g d energy lost by puck
Ff = μ m g = m a deceleration of puck due to friction
a = μ g = 9.8 * .2 = 1.96 m/s^2
v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s speed of puck on striking box
m v2 = M V conservation of momentum when puck strikes box
V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s speed of box after collision
KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J KE of box after collision
KE = μ M g d energy lost by box in sliding distance d
d = 23.3 / (.3 * .8 * 9.8) = 9.91 m distance box slides
