All categories

3 years ago

brooklyn bought 8 bags of the same dog food. She has a $5 coupon. She spent $91. How much was each bad of dog food?

Mathematics

1 answer:

blsea [12.9K]3 years ago

5 0

Answer:

$12

Step-by-step explanation:

Hi there!

What we know:

Brooklyn bought 8 bags of dog food
Brooklyn also used a $5 coupon
The total was $91

Therefore, 8 × (cost of 1 bag) - 5 = 91

Form an equation with x as the cost of 1 bag of dog food:

8 × (cost of 1 bag) - 5 = 91

$8x-5=91$

Add 5 to both sides

$8x-5+5=91+5\\8x=96\\$

Divide both sides by 8

$\frac{8x}{8} = \frac{96}{8} \\x=12$

Therefore, 1 bag of dog food costs $12.

I hope this helps!

You might be interested in

Solve for e E= mc2 m=3 c=6 what is the answer please

alina1380 [7]

E=mc^2 if m=3 and c=6

e=3(6^2)

e=3(36)

e=108

8 0

3 years ago

Read 2 more answers

HELP PLEASE ILL GIVE BRAINLIEST!

yulyashka [42]

It should be 3 because you are going to be using the formation of 3√ 3•3•3

4 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

OLga [1]

y^2(y^2+6) + 6(y^2+6)

(y^2+6)^2

4 0

4 years ago

a standard deck of cards missing the queen of hearts in the 2 of clubs what is the probability of pulling either an ace or a spa

Butoxors [25]

<h3>Answer: 8/25</h3>

=======================================================

Explanation:

In a standard deck, there are 52 cards.

If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.

There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.

Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.

-----------------

The event space has A = 16 cards in it, while the sample space has B = 50 cards.

The probability we're after is A/B = 16/50 = 8/25

5 0

2 years ago

HELP...The volume of a rectangular prism is 36x^6y^8. The length of the prism is 4x^3y^5, and the width of the prism is 3xy^2. W

Margaret [11]

Answer:

$H = 3x^2y$

Step-by-step explanation:

Given

$V = 36x&^6y^8$

$L = 4x^3y^5$

$W = 3xy^2$

Required

Find the height of the prism

Volume (V) is calculated as:

$V =LWH$

Substitute values for V, L and W

$36x^6y^8 =4x^3y^5 * 3xy^2 * H$

Make H the subject

$H = \frac{36x^6y^8}{4x^3y^5 * 3xy^2}$

$H = \frac{36x^6y^8}{4*3x^3*x*y^5y^2}$

$H = \frac{36x^6y^8}{12x^4*y^7}$

Divide:

$H = 3x^{6-4}y^{8-7}$

$H = 3x^2y$

The height of the prism is: $3x^2y$

4 0

3 years ago